Six friends all use $2-off coupons to buy themselves movie tickets. They spend a total of $42. What is the price of one movie ticket without the coupon?

Let's denote the original price of one movie ticket (without the coupon) as $ x $. Each friend has a $2-off coupon, so the price each person pays for a ticket is $ x - 2 $.

Since there are six friends, the total cost of all the tickets is given by:

\[
6 \times (x - 2)
\]

We know that the total amount spent is $42, so we set up the equation:

\[
6 \times (x - 2) = 42
\]

Now, let's solve for $ x $:

1. Divide both sides of the equation by 6:
   
\[
x - 2 = \frac{42}{6} = 7
\]

2. Add 2 to both sides to isolate $ x $:

\[
x = 7 + 2 = 9
\]

So, the price of one movie ticket without the coupon is **$9**.

Would you like more details or have any questions about the solution? 

Here are some related questions to explore further:

1. What would be the total cost if they had used $3-off coupons instead?
2. If the original ticket price was $12, how much would they save in total using $2-off coupons?
3. How much does each friend save individually with the $2-off coupon?
4. How would the equation change if only five friends used coupons?
5. What if one friend didn't use a coupon, how much would the total be then?

**Tip:** When solving word problems, translating the problem into an equation can simplify finding the solution.

Learn how to find the original price of a movie ticket when six friends use $2-off coupons, spending a total of $42. This problem covers key algebraic concepts and basic linear equations, suitable for students in Grades 6-8.

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