To solve the problem, I will assume you are asking to order the angles or side lengths of the triangle from least to greatest based on the diagram.

Given:

• $BC = 13 \, \text{m}$
• $BD = 9 \, \text{m}$
• $CD = 8 \, \text{m}$

Now, let's break it down:

In a triangle, the side opposite the largest angle is the longest, and the side opposite the smallest angle is the shortest.

We can use this concept to order the angles based on their opposite sides:

• $\angle D$ is opposite side $BC = 13 \, \text{m}$
• $\angle B$ is opposite side $CD = 8 \, \text{m}$
• $\angle C$ is opposite side $BD = 9 \, \text{m}$

Thus, ordering the angles by their side lengths:

• $\angle B$ is the smallest (opposite 8 m)
• $\angle C$ is medium (opposite 9 m)
• $\angle D$ is the largest (opposite 13 m)

Order from least to greatest:

$\angle B < \angle C < \angle D$

Would you like further details on this, or any clarifications?

Here are some related questions to explore:

1. How can we use the Law of Cosines to find the angles of this