Math Problem Statement
Solution
To solve the given problem involving the Norman window, let's break it down step-by-step.
1. Understanding the components:
- The window consists of:
- A semicircle at the top with radius .
- A rectangle below the semicircle, with:
- Width (since the width of the rectangle equals the diameter of the semicircle).
- Height (denoted in the figure).
2. Perimeter constraint:
The perimeter of the Norman window includes:
- The semicircle's curved edge: (half of the circumference of a full circle).
- The two vertical sides of the rectangle: .
- The bottom side of the rectangle: (same as the diameter of the semicircle).
Thus, the total perimeter is:
3. Optimization goal:
We need to maximize the area to allow the most light. The total area consists of:
- Area of the semicircle: .
- Area of the rectangle: .
Thus, the total area is:
4. Solve for in terms of using the perimeter:
From the perimeter equation: Rearrange to solve for :
5. Express the area in terms of only:
Substitute the expression for into the area formula:
Simplify:
6. Maximize the area:
To find the value of that maximizes the area, take the derivative of with respect to and set it equal to zero:
7. Calculate the corresponding :
Now that we have , substitute it into the equation for :
Using , you can substitute this value into the expression to compute .
Would you like me to proceed with the numerical calculation for these values or clarify any step?
5 Related Questions:
- How do we ensure this critical point yields the maximum area?
- What is the area of the Norman window with these dimensions?
- How does the perimeter constraint limit the design?
- What happens if the perimeter was increased or decreased?
- Can calculus guarantee the most optimal dimensions in all cases?
Tip:
Always verify your derivative calculations to ensure you correctly identify critical points for optimization problems.
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Math Problem Analysis
Mathematical Concepts
Calculus
Optimization
Geometry
Formulas
Perimeter: πr + 2w + 2r = 23 ft
Area of semicircle: (1/2)πr^2
Area of rectangle: 2r * w
Total area: (1/2)πr^2 + 2r * w
Theorems
First Derivative Test for Optimization
Geometry of Circles and Rectangles
Suitable Grade Level
Grade 11-12, Early College
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