Math Problem Statement

A Norman window has the shape of a rectangle surmounted by a semicircle of diameter equal to the width of the rectangle. If the perimeter of the window is 12 feet, what dimensions will admit the most light (maximize the area)?

Solution

This problem describes a "Norman window," which consists of a rectangle surmounted by a semicircle. The objective is to maximize the area of the window while keeping the perimeter constant at 12 feet.

Here’s a step-by-step approach to solve it:

Step 1: Define variables

Let:

  • ww be the width of the rectangle, which is also the diameter of the semicircle.
  • hh be the height of the rectangle.
  • rr be the radius of the semicircle, so r=w2r = \frac{w}{2}.

Step 2: Write the perimeter equation

The perimeter consists of:

  • The perimeter of the semicircle (half the circumference of a full circle), which is 122πr=πr=πw2\frac{1}{2} \cdot 2\pi r = \pi r = \pi \frac{w}{2}.
  • The height of the rectangle, counted twice (once for each vertical side), which is 2h2h.
  • The width of the rectangle ww.

Thus, the total perimeter is: w+2h+πw2=12w + 2h + \pi \frac{w}{2} = 12 This simplifies to: w+2h+πw2=12w + 2h + \frac{\pi w}{2} = 12 This is the equation for the perimeter.

Step 3: Write the area equation

The total area AA consists of:

  • The area of the rectangle: Arectangle=whA_{\text{rectangle}} = w \cdot h.
  • The area of the semicircle: Asemicircle=12πr2=12π(w2)2=πw28A_{\text{semicircle}} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi \left( \frac{w}{2} \right)^2 = \frac{\pi w^2}{8}.

Thus, the total area is: A=wh+πw28A = w \cdot h + \frac{\pi w^2}{8}

Step 4: Solve for hh

From the perimeter equation: 2h=12wπw22h = 12 - w - \frac{\pi w}{2} h=12wπw22h = \frac{12 - w - \frac{\pi w}{2}}{2}

Step 5: Substitute hh into the area equation

Substitute this expression for hh into the area equation to get a function of A(w)A(w). Then, maximize the area by taking the derivative of A(w)A(w) with respect to ww, setting it equal to zero, and solving for ww.

Would you like further details on finding the specific width and height that maximize the area? Let me know if you have any questions or need more guidance.

Here are 5 follow-up questions that might help you explore this problem further:

  1. How do you differentiate the area equation to find the maximum?
  2. What is the physical interpretation of the critical points found when solving A(w)=0A'(w) = 0?
  3. How does the perimeter constraint affect the possible dimensions of the window?
  4. What role does the semicircle play in maximizing the window’s area compared to a simple rectangular window?
  5. How does changing the perimeter affect the optimal dimensions of the window?

Tip: When solving optimization problems, always ensure that the critical points you find satisfy the given constraints.

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Math Problem Analysis

Mathematical Concepts

Optimization
Geometry
Quadratic Equations

Formulas

Perimeter equation: w + 2h + (πw)/2 = 12
Area equation: A = w * h + (πw²)/8

Theorems

Optimization using calculus: find maximum area by solving A'(w) = 0

Suitable Grade Level

Grades 10-12