Math Problem Statement

L= 0.8logX+0.2logY+λ(5000-4x-2Y)

Solution

To solve this function or optimize it, we will need to address it step-by-step. Let's break down the given function:

L=0.8logX+0.2logY+λ(50004X2Y)L = 0.8 \log X + 0.2 \log Y + \lambda (5000 - 4X - 2Y)

where XX, YY, and λ\lambda (likely a Lagrange multiplier) are variables.

Step 1: Lagrange Multiplier

The given expression looks like it involves the method of Lagrange multipliers for optimization under a constraint. The constraint seems to be 50004X2Y=05000 - 4X - 2Y = 0, based on the λ\lambda term.

If you want to maximize or minimize LL, you'll need to:

Step 2: Partial Derivatives

To apply the method of Lagrange multipliers, you should take the partial derivatives of LL with respect to XX, YY, and λ\lambda, and set them equal to zero to solve for the critical points.

  1. Partial derivative with respect to XX:

LX=0.8X4λ=0\frac{\partial L}{\partial X} = \frac{0.8}{X} - 4\lambda = 0

  1. Partial derivative with respect to YY:

LY=0.2Y2λ=0\frac{\partial L}{\partial Y} = \frac{0.2}{Y} - 2\lambda = 0

  1. Partial derivative with respect to λ\lambda:

Lλ=50004X2Y=0\frac{\partial L}{\partial \lambda} = 5000 - 4X - 2Y = 0

Step 3: Solving the System of Equations

You now have a system of three equations:

  1. 0.8X=4λ\frac{0.8}{X} = 4\lambda
  2. 0.2Y=2λ\frac{0.2}{Y} = 2\lambda
  3. 50004X2Y=05000 - 4X - 2Y = 0

We can solve these equations to find XX, YY, and λ\lambda.

From Equation (1):

λ=0.84X=0.2Y\lambda = \frac{0.8}{4X} = \frac{0.2}{Y} This gives the relationship Y=4XY = 4X.

Substituting Y=4XY = 4X into Equation (3):

50004X2(4X)=05000 - 4X - 2(4X) = 0 500012X=05000 - 12X = 0 X=500012=416.67X = \frac{5000}{12} = 416.67

Substituting X=416.67X = 416.67 into Y=4XY = 4X:

Y=4(416.67)=1666.67Y = 4(416.67) = 1666.67

Step 4: Conclusion

The optimal values of XX and YY are approximately: X416.67,Y1666.67X \approx 416.67, \quad Y \approx 1666.67 You can find λ\lambda from these values by substituting into one of the earlier equations.


Would you like further clarification on any step? Here are 5 related questions to extend this topic:

  1. How do we apply the method of Lagrange multipliers to other optimization problems?
  2. What is the significance of logarithmic functions in optimization problems?
  3. How do you interpret λ\lambda in this type of optimization problem?
  4. Could we solve this numerically if exact solutions weren't possible?
  5. How do logarithmic derivatives help in economics or growth models?

Tip: Always check the constraints carefully in optimization problems to ensure you're not missing any additional limitations.

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Math Problem Analysis

Mathematical Concepts

Optimization
Lagrange Multipliers
Logarithmic Functions

Formulas

L = 0.8logX + 0.2logY + λ(5000 - 4X - 2Y)
Partial derivatives: dL/dX = 0, dL/dY = 0, dL/dλ = 0
Y = 4X
5000 - 12X = 0

Theorems

Lagrange Multiplier Theorem

Suitable Grade Level

University Level (Calculus, Multivariable Calculus)