Math Problem Statement
A cylindrical can has a volume of 686 pi cm cubed. What dimensions yield the minimum surface area? Question content area bottom Part 1 The radius of the can with the minimum surface area is enter your response here cm. (Simplify your answer.) Part 2 The height of the can with the minimum surface area is enter your response here cm. (Simplify your answer.)
Solution
To solve for the dimensions that yield the minimum surface area of the cylindrical can, we use the following steps:
Part 1: The Radius of the Can with Minimum Surface Area
Given the volume , the volume of a cylinder is calculated by: where is the radius and is the height.
From this equation, we can solve for in terms of :
Next, the surface area of a cylinder (including the top and bottom) is given by: Substitute into the surface area formula: Simplify the expression:
To minimize the surface area, we need to take the derivative of with respect to and set it equal to zero: Set this equal to zero: Divide both sides by : Multiply both sides by to eliminate the fraction: Solve for :
Part 2: The Height of the Can with Minimum Surface Area
Now that we have the radius, , substitute it into the equation for height:
Final Answer:
- Radius:
- Height:
Would you like more details on any part of this process?
Here are 5 questions to expand on this:
- What would happen to the surface area if the volume were doubled?
- Can you derive the formula for the surface area of a cylinder from basic principles?
- What is the significance of the derivative in finding the minimum surface area?
- How does the ratio of height to radius affect the surface area?
- Can this optimization technique be applied to other shapes?
Tip: Optimization problems often involve taking derivatives to find minimum or maximum values by identifying critical points.
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Math Problem Analysis
Mathematical Concepts
Geometry
Optimization
Derivatives
Cylindrical Volume and Surface Area
Formulas
Volume of a cylinder: V = πr²h
Surface area of a cylinder: S = 2πr² + 2πrh
Derivative of surface area with respect to radius: dS/dr = 4πr - 1372π/r²
Theorems
Critical points found using derivatives
Optimization of functions using calculus
Suitable Grade Level
Grades 10-12