Math Problem Statement

At Center Hospital there is some concern about the high turnover of nurses. A survey was done to determine how long (in months) nurses had been in their current positions. The responses (in months) of 20 nurses were as follows.

5, 8, 10, 11, 11, 14, 15, 17, 23, 26, 26, 28, 29, 30, 31, 32, 34, 39, 39, 45 (c) Find the value on the data. Locator = Incorrect

Incorrect

(d) Find the value on the data. Locator = Incorrect

Incorrect

(e) Find the value on the data.

Incorrect

(f) Find the of the data.

Incorrect

(g) What are the Upper and Lower limits of the boxplot? Upper Limit = Incorrect

Lower Limit =

Solution

To address your questions systematically, I’ll calculate each requested value step by step. We'll use the given data:

Data (in months): 5, 8, 10, 11, 11, 14, 15, 17, 23, 26, 26, 28, 29, 30, 31, 32, 34, 39, 39, 45

Step-by-Step Calculations:

(c) Calculate the value (Quartile 1, Q1):

  1. Arrange the data in ascending order (already done).

  2. Locate Q1 using the formula: Q1=Value at position n+14Q_1 = \text{Value at position } \frac{n+1}{4}, where n=20n = 20 (number of data points).

    Q1=Value at position 20+14=Value at position 5.25Q_1 = \text{Value at position } \frac{20+1}{4} = \text{Value at position } 5.25

    Since 5.25 is between 5th and 6th positions, interpolate:

    • 5th value = 11
    • 6th value = 14
    • Interpolation: 11+0.25×(1411)=11+0.75=11.7511 + 0.25 \times (14 - 11) = 11 + 0.75 = 11.75

    Q1 = 11.75

(d) Calculate the value (Median/Q2):

  1. Median is the value at position n+12\frac{n+1}{2}: Q2=Value at position 20+12=Value at position 10.5Q_2 = \text{Value at position } \frac{20+1}{2} = \text{Value at position } 10.5

    Interpolate:

    • 10th value = 26
    • 11th value = 26
    • Median: 26+0.5×(2626)=2626 + 0.5 \times (26 - 26) = 26

    Q2 (Median) = 26

(e) Calculate the value (Quartile 3, Q3):

  1. Locate Q3 using the formula: Q3=Value at position 3×n+14=3×20+14=Value at position 15.75Q_3 = \text{Value at position } 3 \times \frac{n+1}{4} = 3 \times \frac{20+1}{4} = \text{Value at position } 15.75

    Interpolate:

    • 15th value = 31
    • 16th value = 32
    • Interpolation: 31+0.75×(3231)=31+0.75=31.7531 + 0.75 \times (32 - 31) = 31 + 0.75 = 31.75

    Q3 = 31.75

(f) Interquartile Range (IQR):

IQR=Q3Q1=31.7511.75=20IQR = Q_3 - Q_1 = 31.75 - 11.75 = 20

(g) Upper and Lower Limits of the Boxplot:

The limits are calculated as:

  1. Lower Limit: Q11.5×IQRQ_1 - 1.5 \times IQR Lower Limit=11.751.5×20=11.7530=18.25\text{Lower Limit} = 11.75 - 1.5 \times 20 = 11.75 - 30 = -18.25

  2. Upper Limit: Q3+1.5×IQRQ_3 + 1.5 \times IQR Upper Limit=31.75+1.5×20=31.75+30=61.75\text{Upper Limit} = 31.75 + 1.5 \times 20 = 31.75 + 30 = 61.75

Final Answers:

  • (c) Q1 = 11.75
  • (d) Median (Q2) = 26
  • (e) Q3 = 31.75
  • (f) IQR = 20
  • (g) Upper Limit = 61.75, Lower Limit = -18.25

Would you like more details on any step or explanation?
Here are 5 related questions:

  1. How do you calculate specific percentiles of a dataset?
  2. What is the difference between quartiles and percentiles?
  3. How does IQR help detect outliers in a dataset?
  4. Can the boxplot limits vary based on different datasets?
  5. Why is interpolation used when locating quartile positions?

Tip: Always double-check dataset sorting before performing quartile calculations.

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Math Problem Analysis

Mathematical Concepts

Descriptive Statistics
Quartiles
Median
Interquartile Range (IQR)
Boxplot Limits

Formulas

Q1 = Value at (n+1)/4 position
Q2 (Median) = Value at (n+1)/2 position
Q3 = Value at 3(n+1)/4 position
IQR = Q3 - Q1
Lower Limit = Q1 - 1.5 * IQR
Upper Limit = Q3 + 1.5 * IQR

Theorems

Quartile Calculation Method
IQR as a Measure of Variability

Suitable Grade Level

Grades 10-12