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The question you provided asks: 

**"What number has 4 fewer tens and 3 fewer ones than a number with 8 tens and 9 ones?"**

Let's break it down:

1. The original number has 8 tens and 9 ones:
   - 8 tens = 80
   - 9 ones = 9
   - So, the original number is **80 + 9 = 89**.

2. Now, subtract 4 tens and 3 ones:
   - 4 fewer tens: \( 8 - 4 = 4 \) tens, which is 40.
   - 3 fewer ones: \( 9 - 3 = 6 \) ones.

3. The new number has 4 tens and 6 ones:
   - 4 tens = 40
   - 6 ones = 6
   - So, the new number is **40 + 6 = 46**.

Therefore, the number you're looking for is **46**.

Would you like more details or further clarification?

Here are some related questions for further understanding:
1. How do place values (tens and ones) affect the value of a number?
2. How do you subtract different digits from tens and ones positions?
3. Can you create a number with fewer tens but more ones than the original?
4. What happens to a number when you add tens or ones to it?
5. How do you estimate numbers when subtracting multiple digits?

**Tip**: Always align place values carefully when performing arithmetic to avoid mistakes!

What number has 4 fewer tens and 3 fewer ones than a number with 8 tens and 9 ones?

Solve the problem where you need to find the number that has 4 fewer tens and 3 fewer ones than a number with 8 tens and 9 ones. This problem focuses on place value and subtraction, suitable for students in Grades 2-4.

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