Let's break down the problem using the information provided.

Let the four-digit number be represented as $ABCD$, where:

• $A$ is the thousands digit,
• $B$ is the hundreds digit,
• $C$ is the tens digit,
• $D$ is the ones digit.

The problem gives us the following relationships:

1. The thousands digit $A$ is 4 greater than the hundreds digit $B$: $A = B + 4$

2. The tens digit $C$ is two times the thousands digit $A$: \