Math Problem Statement
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1000 and the standard deviation is $85.
745 830 915 1000 1085 1170 1255 Distribution of Prices [Graphs generated by this script: setBorder(10,30,10,5);initPicture(-3.5,3.5,-.1,.45);line([-88.5,0],[88.5,0]);line([-3,.02],[-3,-.02]);text([-3,-.01],"745","below");line([-2,.02],[-2,-.02]);text([-2,-.01],"830","below");line([-1,.02],[-1,-.02]);text([-1,-.01],"915","below");line([0,.02],[0,-.02]);text([0,-.01],"1000","below");line([1,.02],[1,-.02]);text([1,-.01],"1085","below");line([2,.02],[2,-.02]);text([2,-.01],"1170","below");line([3,.02],[3,-.02]);text([3,-.01],"1255","below");textabs([200,0],'Distribution of Prices','above');fill="none";path([[-3.5,0.00087268270248894],[-3.4125,0.0011808548546798],[-3.325,0.0015856655971737],[-3.2375,0.0021130103340165],[-3.15,0.0027942584387119],[-3.0625,0.00366696237757],[-2.975,0.0047755266178224],[-2.8875,0.006171788271972],[-2.8,0.0079154516504915],[-2.7125,0.01007431010247],[-2.625,0.012724181705357],[-2.5375,0.015948481633483],[-2.45,0.01983735456099],[-2.3625,0.024486296371885],[-2.275,0.029994206738768],[-2.1875,0.036460833487169],[-2.1,0.043983596355567],[-2.0125,0.052653811509711],[-1.925,0.062552378033174],[-1.8375,0.073745031931229],[-1.75,0.086277319562377],[-1.6625,0.10016948780033],[-1.575,0.1154115290627],[-1.4875,0.13195865176446],[-1.4,0.14972746691278],[-1.3125,0.16859318595606],[-1.225,0.1883881108589],[-1.1375,0.20890166300605],[-1.05,0.22988214264492],[-0.9625,0.25104033647462],[-0.875,0.27205500069892],[-0.7875,0.2925801450485],[-0.7,0.31225393603],[-0.6125,0.33070893210235],[-0.525,0.34758326725691],[-0.4375,0.36253232013251],[-0.35,0.37524035011739],[-0.2625,0.3854315552717],[-0.175,0.39288001279828],[-0.087500000000002,0.39741800230538],[-2.3037127760972E-15,0.39894228380404],[0.087499999999998,0.39741800230538],[0.175,0.39288001279828],[0.2625,0.3854315552717],[0.35,0.37524035011739],[0.4375,0.36253232013251],[0.525,0.34758326725691],[0.6125,0.33070893210235],[0.7,0.31225393603],[0.7875,0.2925801450485],[0.875,0.27205500069892],[0.9625,0.25104033647462],[1.05,0.22988214264492],[1.1375,0.20890166300605],[1.225,0.1883881108589],[1.3125,0.16859318595606],[1.4,0.14972746691278],[1.4875,0.13195865176446],[1.575,0.1154115290627],[1.6625,0.10016948780033],[1.75,0.086277319562378],[1.8375,0.073745031931229],[1.925,0.062552378033175],[2.0125,0.052653811509711],[2.1,0.043983596355567],[2.1875,0.03646083348717],[2.275,0.029994206738769],[2.3625,0.024486296371886],[2.45,0.01983735456099],[2.5375,0.015948481633483],[2.625,0.012724181705357],[2.7125,0.01007431010247],[2.8,0.0079154516504916],[2.8875,0.0061717882719721],[2.975,0.0047755266178225],[3.0625,0.0036669623775701],[3.15,0.0027942584387119],[3.2375,0.0021130103340166],[3.325,0.0015856655971737],[3.4125,0.0011808548546798],[3.5,0.00087268270248895]]);]
What is the approximate percentage of buyers who paid between $1000 and $1085? %
What is the approximate percentage of buyers who paid more than $1255? %
What is the approximate percentage of buyers who paid between $745 and $1000? 49.87 Correct%
What is the approximate percentage of buyers who paid between $915 and $1085? %
What is the approximate percentage of buyers who paid less than $830? %
What is the approximate percentage of buyers who paid between $830 and $1000? %
Solution
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Math Problem Analysis
Mathematical Concepts
Statistics
Normal Distribution
Probability
Formulas
z = (x - μ) / σ
Theorems
Properties of Normal Distribution
68-95-99.7 Rule
Suitable Grade Level
Grades 10-12
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