From the calculations in the image, let's analyze the context of where the numbers $1.22$ and $24$ come from:

1. Context of $1.22$:

   • The formula used here is $a = \frac{F_{\text{net}}}{m}$, where:

     • $F_{\text{net}}$ is the net force acting on the object.
     • $m$ is the mass of the object.

   • From the image:

     • $F_{\text{net}} = 24 \, \text{N}$ (calculated earlier).
     • The denominator $m = 1.22 \, \text{kg}$ seems to represent the mass of the object.

   • However, the mass value ($1.22$) is not explicitly shown in the problem setup in the image, so it must have been either:

     • A given value from the original problem statement not shown here.
     • Or an assumed value.

   Without further context, we cannot confirm where the mass $1.22 \, \text{kg}$ originates from, but it’s used here to find the acceleration ($a$).

2. Context of $24$:

   • The net force, $F_{\text{net}} = F_{\text{app}} - F_f$, is calculated step by step:

     • $F_{\text{app}} = 30 \, \text{N}$.
     • Frictional force $F_f = 6 \, \text{N}$ (calculated as $\mu \cdot F_{\text{norm}} = 0.5 \cdot 12 = 6$).
     • Therefore: $F_{\text{net}} = 30 - 6 = 24 \, \text{N}.$

   • This value ($24 \, \text{N}$) is correct based on the provided numbers.

Explanation:

• The $1.22 \, \text{kg}$ mass seems unexplained in the problem as presented, and its origin might be external to this snippet.
• The $24 \, \text{N}$ is a direct result of the net force calculation, which is valid.

Would you like me to clarify further or analyze any specific step?

5 Related Questions:

1. Why is the frictional force calculated using $\mu \cdot F_{\text{norm}}$?
2. How does the acceleration change if the mass value is different?
3. Could the $1.22 \, \text{kg}$ mass be derived from earlier problem context?
4. Why does $F_{\text{norm}} = 12 \, \text{N}$ in this problem?
5. How is net force conceptually linked to acceleration?

Tip:

Always verify given or assumed values (like mass in this case) when interpreting solutions to ensure all constants are consistent with the problem setup.