Math Problem Statement

Letf:R2{0}→Rbe the function defined byf(x,y)=xaybxm+yn,wheremandnare positive even numbers anda,b∈R. Discuss the behavioroffwhen(x,y)approaches the origin.1

Solution

The function f(x,y)=xaybxm+ynf(x, y) = x^a y^b x^m + y^n, defined on R2{0}\mathbb{R}^2 \setminus \{0\}, where mm and nn are positive even numbers, and a,bRa, b \in \mathbb{R}, can be analyzed as (x,y)(0,0)(x, y) \to (0, 0).

Step-by-Step Analysis

  1. Understanding the Behavior Near the Origin: We are interested in how the function behaves as (x,y)(x, y) approaches the origin (0,0)(0, 0). To do so, we must examine the limits along different paths approaching the origin and check for consistency.

  2. General Form of the Function: The function is given by: f(x,y)=xaybxm+ynf(x, y) = x^a y^b x^m + y^n which can be split into two terms:

    • The first term: xaybxm=xa+mybx^a y^b x^m = x^{a+m} y^b
    • The second term: yny^n
  3. Limit Along Different Paths: To understand the limit behavior, it's useful to approach the origin along various straight lines and curves:

    • Along the x-axis (where y=0y = 0): f(x,0)=xa+m0b+0n=0f(x, 0) = x^{a+m} \cdot 0^b + 0^n = 0 Thus, along the x-axis, f(x,y)0f(x, y) \to 0 as x0x \to 0.

    • Along the y-axis (where x=0x = 0): f(0,y)=0a+myb+yn=ynf(0, y) = 0^{a+m} y^b + y^n = y^n Since nn is even, as y0y \to 0, f(0,y)0f(0, y) \to 0.

    • Along a line y=mxy = mx (for some constant mm): Substituting y=mxy = mx into the function: f(x,mx)=xa+m(mx)b+(mx)nf(x, mx) = x^{a+m} (mx)^b + (mx)^n This simplifies to: f(x,mx)=mbxa+m+b+mnxnf(x, mx) = m^b x^{a+m+b} + m^n x^n As x0x \to 0, the behavior of f(x,mx)f(x, mx) depends on the powers of xx. Specifically:

      • If a+m+b>na + m + b > n, the term mbxa+m+bm^b x^{a+m+b} will dominate, and f(x,mx)0f(x, mx) \to 0.
      • If a+m+b<na + m + b < n, the term mnxnm^n x^n will dominate, and f(x,mx)0f(x, mx) \to 0.
      • If a+m+b=na + m + b = n, the limit depends on the constants involved but should approach zero as well.
  4. Conclusion on Limit: The behavior of f(x,y)f(x, y) as (x,y)(0,0)(x, y) \to (0, 0) is generally 0 along various paths as long as mm and nn are positive even numbers. The function has a strong tendency to approach 0 along straight lines and curves, indicating that the limit is likely 0 as (x,y)(0,0)(x, y) \to (0, 0).

    However, to formally prove this, one could use polar coordinates or other methods, but the above reasoning gives a solid indication that the limit is indeed 0 at the origin.


Would you like to explore the behavior in more detail (e.g., using polar coordinates or another method), or do you have any questions about this analysis?

Related Questions:

  1. How would the behavior of the function change if mm and nn were odd numbers instead of even?
  2. What happens to the limit if we allow xx and yy to approach the origin along a curve other than a straight line?
  3. How can polar coordinates be used to further confirm the behavior of this function at the origin?
  4. What would happen to the function if the powers aa and bb were both negative?
  5. How do the signs of aa and bb affect the limit behavior of the function?

Tip:

To study the limit in more general settings, it can be helpful to express the function in polar coordinates (r,θ)(r, \theta), where x=rcos(θ)x = r \cos(\theta) and y=rsin(θ)y = r \sin(\theta), and analyze how the function behaves as r0r \to 0.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Limits
Function Behavior
Path Limits
Polar Coordinates

Formulas

f(x, y) = x^a y^b x^m + y^n

Theorems

Limit Theorem
Path-Dependent Limits
Polar Coordinate Transformation

Suitable Grade Level

College/University (Calculus Level)