Math Problem Statement

give Reason that no matter which integer you multiply by an even number, the answer will be an even number.

Solution

The reason that multiplying any integer by an even number always results in an even number lies in the properties of even numbers.

Explanation:

  1. Definition of an Even Number: An even number is any integer that can be written in the form 2k2k, where kk is an integer. This means that an even number is always divisible by 2.

  2. Multiplying an Even Number by Any Integer: When you multiply an even number 2k2k by any integer nn, the result is: (2k)×n=2(kn)(2k) \times n = 2(kn) This shows that the result is 2×(kn)2 \times (kn), which is clearly a multiple of 2.

  3. Conclusion: Since the result 2(kn)2(kn) is divisible by 2, it is always an even number, regardless of the value of nn.

Therefore, the key reason is that the factor of 2 in an even number is preserved in the product, making the result always even.

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Related Questions:

  1. What is the definition of an odd number, and why does multiplying an odd number by an even number also result in an even number?
  2. How does adding two even numbers together result in another even number?
  3. What is the result when you multiply two odd numbers? Why?
  4. Can an even number ever be the result of multiplying two odd numbers? Why or why not?
  5. What happens when you divide an even number by 2? Will it always result in an integer?

Tip:

Always check for divisibility by 2 when determining if a number is even. If it’s divisible by 2, it is always even.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Multiplication
Even and Odd Numbers

Formulas

(2k) × n = 2(kn)

Theorems

Properties of Even Numbers

Suitable Grade Level

Grades 6-8