if one adds 2 to itself 4 times one gets 2+2+2+2=8, what do you get if one adds 2 to itself n times, one gets 

If you add \(2\) to itself \(n\) times, the resulting sum would be:

\[
2 + 2 + 2 + \dots + 2 \quad (\text{with } n \text{ terms})
\]

This can be expressed as a repeated addition, which is equivalent to multiplication:

\[
2 \times n = 2n
\]

So, if one adds \(2\) to itself \(n\) times, one gets \(2n\).

Would you like further details, or do you have any questions?

Here are some related questions:

1. What if you add a different number, say \(3\), to itself \(n\) times?
2. How does this concept relate to exponents or powers?
3. What if you add \(2\) to itself \(n\) times but skip every second term?
4. How would you express adding \(2\) to itself \(n\) times using a summation notation?
5. How does this pattern change if each added term increases by \(1\)?

**Tip:** Repeated addition is a fundamental concept leading to multiplication.

if one adds 2 to itself 4 times one gets 2+2+2+2=8, what do you get if one adds 2 to itself n times, one gets

Discover the solution to adding 2 to itself n times, resulting in 2n. This concept explores the basics of repeated addition and its relationship to multiplication, suitable for Grades 4-6 students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation