The expression provided in the image is:

$(2 - 6i)(4 - 2i)$

Let's multiply these two complex numbers using the distributive property (FOIL method):

$(2 - 6i)(4 - 2i) = 2 \cdot 4 + 2 \cdot (-2i) + (-6i) \cdot 4 + (-6i) \cdot (-2i)$

Now, calculate each term:

1. $2 \cdot 4 = 8$
2. $2 \cdot (-2i) = -4i$
3. $(-6i) \cdot 4 = -24i$
4. $(-6i) \cdot (-2i) = 12i^2$, and since $i^2 = -1$, this becomes $12(-1) = -12$

Now, combine all terms:

$8 - 4i - 24i - 12 = (8 - 12) + (-4i - 24i) = -4 - 28i$

So, the product is:

$-4 - 28i$

Would you like more details on this solution or have any questions?

Here are some related questions:

1. How do you multiply two complex numbers in general?
2. What does $i^2 = -1$ represent, and why is it important in complex numbers?
3. Can the distributive property be applied to any two complex numbers?
4. What is the geometric interpretation of multiplying two complex numbers?
5. How do you find the magnitude and phase of the resulting complex number?

Tip: When multiplying complex numbers, always remember that $i^2 = -1$, which is essential for simplifying terms involving $i$.