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create video explanation on how the answer is 35cm

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### Problem Recap:
We are given:
- A uniform meter ruler \( AB \) of weight 0.95 N.
- The ruler is supported by a knife edge 45 cm from point \( A \).
- A mass of 48 g (which has a weight \( W = 0.048 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 0.4704 \, \text{N} \)) is suspended at a distance \( x \) from \( A \).
- The system is in equilibrium, meaning the meter ruler balances horizontally.

We are asked to find the distance \( x \) from point \( A \) where the 48 g mass must be placed for the ruler to balance.

### Solution Outline:

1. **Identify the Forces Acting:**
   - Weight of the ruler acts through its center of gravity (G), which is at the midpoint of the ruler, i.e., 50 cm from \( A \).
   - The reaction force \( N \) at the knife edge (pivot) provides no torque because it acts at the pivot.
   - The weight of 48 g (0.4704 N) is acting vertically downward at a distance \( x \) from \( A \).

2. **Apply the Principle of Moments:**
   Since the ruler is in equilibrium, the sum of the clockwise moments about the knife edge must equal the sum of the counterclockwise moments.

   Taking moments about the knife edge (located 45 cm from \( A \)):

   -

A uniform meter ruler AB of weight 0.95 N is supported on a knife edge placed at 45 cm from A. The meter ruler balances horizontally when a mass of 48 g is suspended at a distance x from A. Find the value of x.

Explore how to solve a moments of forces problem involving a uniform meter ruler of weight 0.95 N. This problem demonstrates the principle of moments and torque, requiring the calculation of the distance x from point A where a 48 g mass must be suspended for equilibrium. Suitable for students in Grades 9-11.

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