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To determine the moment about point A caused by the applied force \( F \), we can use the following formula for the moment:

\[
M = F \cdot d \cdot \sin(\theta)
\]

Where:
- \( M \) is the moment about point A.
- \( F \) is the applied force, which is given as \( 5 \, \text{N} \).
- \( d \) is the distance from point A to the point of application of the force, which is \( 3 \, \text{m} \).
- \( \theta \) is the angle between the force and the position vector, which is \( 60^\circ \).

Now we can substitute the values:

\[
M = 5 \, \text{N} \cdot 3 \, \text{m} \cdot \sin(60^\circ)
\]

We know that \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \approx 0.866 \).

\[
M = 5 \cdot 3 \cdot 0.866
\]

Now let's calculate the moment.The moment about point A caused by the applied force is approximately \( 13 \, \text{Nm} \). Based on the available options, the closest answer is \( 12 \, \text{Nm} \).

Would you like further details on the calculations, or do you have any other questions?

Here are 5 related questions for practice:
1. How would the moment change if the angle were \( 90^\circ \)?
2. What if the force applied was doubled but the angle remained the same?
3. How does the moment vary with respect to the distance \( d \)?
4. What happens to the moment if the angle \( \theta \) is \( 0^\circ \)?
5. Can the moment ever be negative, and if so, under what conditions?

**Tip:** Always remember that the moment depends on the perpendicular distance to the line of action of the force!

Determine the moment about point A caused by the applied force F = 5 N at an angle of 60° and a distance of 3 meters from point A.

Learn how to calculate the moment about point A for a force of 5 N applied at an angle of 60° and 3 meters from the point. This statics problem demonstrates how to use the moment formula M = F * d * sin(θ). Suitable for Grades 10-12.

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