Math Problem Statement

The temperature of a specific animal appears to follow a sinusoidal pattern over time. A sine curve can be used to model the situation. During an examination, the maximum temperature of 120°F occurred 14 minutes into the exam. A minimum temperature of 96°F occurred 28 minutes later. What is the sine function?

Solution

Let's analyze the problem step by step:


Problem Recap:

  • The temperature follows a sinusoidal pattern modeled by a sine function f(x)f(x).
  • Maximum temperature: 120120^\circ at t=14minutest = 14 \, \text{minutes}.
  • Minimum temperature: 9696^\circ, which occurs 28minutes28 \, \text{minutes} after the maximum.

Step 1: Determine the midline of the sine wave

The midline is the average of the maximum and minimum temperatures: Midline=Maximum Temperature+Minimum Temperature2=120+962=108\text{Midline} = \frac{\text{Maximum Temperature} + \text{Minimum Temperature}}{2} = \frac{120 + 96}{2} = 108 So, the midline of the sine wave is at y=108y = 108.


Step 2: Determine the amplitude

The amplitude is the difference between the maximum temperature and the midline: Amplitude=Maximum TemperatureMidline=120108=12\text{Amplitude} = \text{Maximum Temperature} - \text{Midline} = 120 - 108 = 12


Step 3: Determine the period

The problem states that the minimum temperature occurs 28 minutes after the maximum temperature. Since a full period spans one complete oscillation (from max to min to max), the total period is: Period=2×28=56minutes\text{Period} = 2 \times 28 = 56 \, \text{minutes}

The formula for the period of a sine wave is: Period=2πb\text{Period} = \frac{2\pi}{b} Solving for bb: b=2πPeriod=2π56=π28b = \frac{2\pi}{\text{Period}} = \frac{2\pi}{56} = \frac{\pi}{28}


Step 4: Phase shift

The sine function normally starts at 00, but the maximum occurs at t=14t = 14. Therefore, the phase shift is 1414. Since the sine function is shifted to the right, this corresponds to a positive phase shift.


Step 5: Write the equation

The general form of a sine function is: f(x)=asin(b(xc))+df(x) = a \sin(b(x - c)) + d Where:

  • a=12a = 12 (amplitude),
  • b=π28b = \frac{\pi}{28} (frequency),
  • c=14c = 14 (phase shift),
  • d=108d = 108 (midline).

Thus, the equation is: f(x)=12sin(π28(x14))+108f(x) = 12 \sin\left(\frac{\pi}{28}(x - 14)\right) + 108


Would you like a detailed explanation for any specific step? Here are five follow-up questions you could explore:

  1. How do we know the period is 2×282 \times 28 instead of just 2828?
  2. What happens if we use a cosine function instead of sine for this scenario?
  3. How does the phase shift affect the graph of the function?
  4. Can we determine the function using the minimum instead of the maximum point?
  5. How do we verify this equation is correct by substituting values?

Tip: Always confirm the midline and amplitude by checking their symmetry between the max and min values!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometric Functions
Sinusoidal Modeling
Amplitude
Period
Phase Shift

Formulas

f(x) = a sin(b(x - c)) + d
Midline = (Maximum + Minimum) / 2
Amplitude = Maximum - Midline
Period = 2π / b

Theorems

-

Suitable Grade Level

Grades 10-12