The speed, in miles per hour, of a race car on a track is modeled by the linear function v(t)=60+1.2t, where t is the number of seconds since the car began its second lap around the track.

The function \( v(t) = 60 + 1.2t \) models the speed of a race car in miles per hour, where \( t \) is the time in seconds since the car started its second lap. 

### Key Points:

1. **Initial Speed**: At \( t = 0 \), the speed is:
   \[
   v(0) = 60 + 1.2(0) = 60 \text{ mph}
   \]

2. **Rate of Change**: The term \( 1.2t \) indicates that the speed increases by 1.2 miles per hour for each second that passes.

3. **Speed After Time**: To find the speed at any time \( t \), simply plug in the value of \( t \) into the function. For example:
   - At \( t = 10 \) seconds:
   \[
   v(10) = 60 + 1.2(10) = 60 + 12 = 72 \text{ mph}
   \]
   - At \( t = 30 \) seconds:
   \[
   v(30) = 60 + 1.2(30) = 60 + 36 = 96 \text{ mph}
   \]

4. **Maximizing Speed**: The function is linear, meaning there is no maximum speed as \( t \) increases; the speed continues to increase indefinitely.

### Questions for Further Exploration:

1. What is the speed of the car after 5 minutes?
2. How long will it take for the car to reach a speed of 100 mph?
3. What would the speed be if the car maintained this rate for 1 hour?
4. How does this model compare to a constant speed model?
5. Can you describe how this model could be used to predict lap times?

### Tip:
Always remember that in linear models, the slope indicates the rate of change, and the y-intercept represents the initial value.

The speed, in miles per hour, of a race car on a track is modeled by the linear function v(t)=60+1.2t, where t is the number of seconds since the car began its second lap around the track.

Explore the linear function v(t) = 60 + 1.2t that models the speed of a race car, detailing its initial speed, rate of change, and speed at various time intervals. This problem is ideal for students in Grades 8-10 learning about linear functions.

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