Math Problem Statement

The milk and water in vessels A and B are in the ratio 5:3 and 3:4 respectively and what resear the liquids in both vessels be mixed to get a new mixture whether C consisting 50% milk and 50% water

Solution

Let the volume of liquid in vessels A and B be represented by some unknown quantities xx and yy, respectively.

The ratios of milk and water in vessels A and B are:

  • In vessel A, the ratio of milk to water is 5:3.

    • This means that the fraction of milk in vessel A is 55+3=58\frac{5}{5+3} = \frac{5}{8} and the fraction of water is 38\frac{3}{8}.
  • In vessel B, the ratio of milk to water is 3:4.

    • This means that the fraction of milk in vessel B is 33+4=37\frac{3}{3+4} = \frac{3}{7} and the fraction of water is 47\frac{4}{7}.

Now, we want to mix the liquids from both vessels to get a new mixture C where the ratio of milk to water is 50:50, i.e., 12\frac{1}{2} milk and 12\frac{1}{2} water.

Let the total amount of liquid taken from vessel A be xx and from vessel B be yy.

  • The amount of milk from vessel A is 58x\frac{5}{8}x, and the amount of water from vessel A is 38x\frac{3}{8}x.
  • The amount of milk from vessel B is 37y\frac{3}{7}y, and the amount of water from vessel B is 47y\frac{4}{7}y.

For the mixture C to be 50% milk and 50% water, the amount of milk in the total mixture should be equal to the amount of water in the total mixture. So, we set up the equation:

58x+37y=38x+47y\frac{5}{8}x + \frac{3}{7}y = \frac{3}{8}x + \frac{4}{7}y

Simplifying this:

58x38x=47y37y\frac{5}{8}x - \frac{3}{8}x = \frac{4}{7}y - \frac{3}{7}y

28x=17y\frac{2}{8}x = \frac{1}{7}y

x4=y7\frac{x}{4} = \frac{y}{7}

Multiplying both sides by 28 to eliminate the fractions:

7x=4y7x = 4y

Thus, the ratio of xx to yy is:

xy=47\frac{x}{y} = \frac{4}{7}

Conclusion:

To get a mixture with 50% milk and 50% water, the liquids from vessels A and B should be mixed in the ratio 4:7.

Would you like further details or have any questions?

Here are 5 related questions to extend this topic:

  1. How would the ratio change if the percentage of milk in vessel C were 60% instead of 50%?
  2. How do you solve for the total volume of the mixture if you know the volumes of vessels A and B?
  3. What if vessel A had a different milk-to-water ratio, say 2:1? How would that affect the solution?
  4. How would you find the exact volume of milk and water if the volumes of vessels A and B were given?
  5. How can you verify that the final mixture meets the desired milk-to-water ratio?

Tip: When dealing with ratios and mixtures, it’s helpful to express all parts of the mixture as fractions to set up balanced equations easily.

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Math Problem Analysis

Mathematical Concepts

Ratios and Proportions
Mixture Problems
Linear Equations

Formulas

Fraction of milk in vessel = (Milk Quantity) / (Total Quantity)
Fraction of water in vessel = (Water Quantity) / (Total Quantity)
Equation: (Milk from A + Milk from B) = (Water from A + Water from B)

Theorems

Basic Ratio Theorem
Proportionality Principle

Suitable Grade Level

Grades 9-12