Math Problem Statement

Solve

In Jar A, there are 10 liters of milk and 6 liters of water. In Jar B, there is 65 liters of a milk and water solution having a milk to water ratio as 10 : x. Jars A and B are emptied into Jar C which has 9 liters of water. If Jar C has 75% milk, then the value of x is:

Solution

The problem in the image states the following:

  • In Jar A, there are 10 liters of milk and 6 liters of water.
  • In Jar B, there is 65 liters of a milk and water solution, where the ratio of milk to water is 10:x10 : x.
  • Jars A and B are emptied into Jar C, which has a total of 9 liters of water.
  • Jar C now has 75% milk.

We are tasked with finding the value of xx (the ratio in Jar B).


Let's break this down:

  1. Jar A:

    • Milk: 10 liters
    • Water: 6 liters
  2. Jar B:

    • Total solution: 65 liters
    • Ratio of milk to water is 10:x10 : x
    • So, the amount of milk in Jar B is 1010+x×65\frac{10}{10+x} \times 65 liters.
    • The amount of water in Jar B is x10+x×65\frac{x}{10+x} \times 65 liters.
  3. Jar C (after combining Jars A and B):

    • Water: 9 liters already + water from Jar A + water from Jar B
    • Milk will be 75% of the total volume of Jar C.

Step 1: Total Milk in Jar C

From Jar A: 10 liters of milk
From Jar B: Milk from Jar B is 1010+x×65\frac{10}{10+x} \times 65.

Total milk in Jar C = 10+1010+x×6510 + \frac{10}{10+x} \times 65.

Step 2: Total Water in Jar C

Water from Jar A: 6 liters
Water from Jar B: x10+x×65\frac{x}{10+x} \times 65 liters
Water already in Jar C: 9 liters

Total water in Jar C = 6+x10+x×65+96 + \frac{x}{10+x} \times 65 + 9.

Step 3: Total Volume in Jar C

The total volume in Jar C (milk + water) is: Total volume=Total milk+Total water.\text{Total volume} = \text{Total milk} + \text{Total water}. This simplifies to: 10+1010+x×65+6+x10+x×65+9.10 + \frac{10}{10+x} \times 65 + 6 + \frac{x}{10+x} \times 65 + 9.

Step 4: Applying the Milk Percentage

It is given that Jar C has 75% milk, so the fraction of milk is: Total milkTotal volume=0.75.\frac{\text{Total milk}}{\text{Total volume}} = 0.75.

Substituting the expressions for total milk and total volume into this equation gives a solvable equation in terms of xx. Solving this will yield the value of xx.


Let me calculate the exact value for you.

Step 5: Solving the Equation

The milk-to-total ratio is 0.750.75, and setting up the equation will give:

10+1010+x×6510+1010+x×65+6+x10+x×65+9=0.75.\frac{10 + \frac{10}{10+x} \times 65}{10 + \frac{10}{10+x} \times 65 + 6 + \frac{x}{10+x} \times 65 + 9} = 0.75.

Multiplying through and solving this equation will give the value of xx.


I'll calculate this for you now:

10+65010+x25+65=0.75\frac{10 + \frac{650}{10+x}}{25 + 65} = 0.75

This simplifies into finding xx.

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Math Problem Analysis

Mathematical Concepts

Ratios
Percentages
Algebra
Mixture Problems

Formulas

Ratio formula: milk to water = milk/water
Percentage formula: percentage = (part/whole) * 100
Total volume = Milk from A + Milk from B + Water from A + Water from B + Water in C

Theorems

Mixture and Alligation Theorem

Suitable Grade Level

Grades 9-12