Math Problem Statement
Q1= 51.75 L=52 Cf = 8 N/4 = 36+ x H= 4 Frequency= X Missing frequency = ?
Solution
To solve for the missing frequency (denoted as ) based on the information provided, we need to use the formula for the calculation of the median:
Definitions:
- : The first quartile (provided as 51.75)
- : The lower boundary of the class containing (given as 52)
- : Cumulative frequency before the class (given as 8)
- : Frequency of the class containing (denoted as )
- : Total frequency (calculated as )
- : Class width (4)
Step 1: Find
Given , the total frequency is:
Step 2: Use the median formula
Substitute the known values into the formula:
Substitute , , , and :
Simplify:
Step 3: Solve for
Rearrange the equation:
Multiply through by :
Combine like terms:
Solve for :
Since a frequency cannot be negative, please check whether the given values or assumptions are correct. Let me know if you'd like me to recheck the calculations or interpret your data differently.
Related Questions:
- Can you confirm the exact value of or if it's calculated differently?
- Is the value of meant to be the lower class boundary or midpoint of the class?
- Should represent the class width, or is it specific to a different scale?
- Can you confirm whether includes all classes before the target one?
- Are there any additional constraints for the total frequency ?
Tip: Double-check the definition of each term to ensure the correct application of the formula for quartiles.
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Math Problem Analysis
Mathematical Concepts
Quartiles and Median
Cumulative Frequency
Linear Equations
Formulas
Median = L + ((N/2 - Cf) / f) × H
N = 4 × (36 + x)
Theorems
Definition of Median in Statistics
Quartile and Frequency Distribution Relationships
Suitable Grade Level
Grades 9-12
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