Math Problem Statement

Numbers are drawn from 973 integers, 27 to 999, at random. At least how many numbers need to be drawn to ensure that there are two numbers drawn whose sum is 659?

Solution

We need to determine the minimum number of integers that must be drawn from the set of integers between 27 and 999 such that we are guaranteed to have two numbers whose sum equals 659.

Step 1: Define the set of integers

The numbers are drawn from the set of integers S={27,28,29,,999}S = \{27, 28, 29, \dots, 999\}. This is a total of 973 integers.

Step 2: Consider pairs of numbers

For any two numbers xx and yy from this set, we are looking for pairs such that their sum is 659: x+y=659x + y = 659 Thus, y=659xy = 659 - x.

Step 3: Identify valid pairs

We need both xx and yy to be in the range of the integers between 27 and 999. Specifically:

  • If x=27x = 27, then y=65927=632y = 659 - 27 = 632.
  • If x=28x = 28, then y=65928=631y = 659 - 28 = 631.
  • If x=29x = 29, then y=65929=630y = 659 - 29 = 630.
  • And so on, continuing this pattern.

The smallest valid xx is 27 and the largest valid xx is 65927=632659 - 27 = 632. So, we are only concerned with pairs where x{27,28,,632}x \in \{27, 28, \dots, 632\} and y=659xy = 659 - x.

Step 4: Count the number of pairs

Each number x{27,28,,632}x \in \{27, 28, \dots, 632\} pairs uniquely with y=659xy = 659 - x, which is also in the set SS. The numbers from 27 to 632 form 606 pairs, since: 63227+1=606632 - 27 + 1 = 606 Thus, there are 606 valid pairs of numbers whose sum is 659.

Step 5: Apply the pigeonhole principle

The pigeonhole principle tells us that if we have more items than containers, then at least one container must hold more than one item. In this case, the "items" are the numbers we draw, and the "containers" are the pairs whose sum is 659.

If we draw 607 numbers, we are guaranteed to have two numbers from the same pair because there are only 606 distinct pairs whose sum is 659. Therefore, the minimum number of numbers we must draw to ensure that two of them sum to 659 is:

607\boxed{607}

Would you like more details or have any questions?

Here are five related questions for further practice:

  1. What if the sum required was 700 instead of 659?
  2. How many numbers need to be drawn to ensure three numbers sum to 659?
  3. What if the integers were drawn from a smaller range, say 50 to 500?
  4. How would the answer change if the

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Math Problem Analysis

Mathematical Concepts

Number Theory
Combinatorics
Pigeonhole Principle

Formulas

x + y = 659
Total pairs = 632 - 27 + 1 = 606

Theorems

Pigeonhole Principle

Suitable Grade Level

Grades 10-12