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We are given that the company offers a 25% discount, and Anurag wants to save at least ₹390 by purchasing a certain number of items that originally cost ₹340 each. Let's break down the problem step by step:

1. **Discount per item**:  
   The price of each item is ₹340, and the discount is 25%. Therefore, the discount per item is:
   \[
   \text{Discount per item} = 25\% \times 340 = \frac{25}{100} \times 340 = 85 \, \text{Rs}.
   \]

2. **Total savings**:  
   Anurag wants to save at least ₹390. Let the number of items Anurag buys be \( n \). His total savings will be:
   \[
   \text{Total savings} = 85n.
   \]

3. **Minimum number of items**:  
   To save at least ₹390, the total savings should be greater than or equal to ₹390. Therefore, we set up the inequality:
   \[
   85n \geq 390.
   \]
   Solving for \( n \):
   \[
   n \geq \frac{390}{85} \approx 4.59.
   \]

   Since \( n \) must be a whole number, we round up to the nearest whole number. Thus, Anurag needs to buy at least **5 items** to save ₹390 or more.

The correct answer is **option 4: 5**.

Would you like any further details or have any questions?

Here are 5 related questions:
1. If the discount was 30%, how many items would Anurag need to buy to save ₹390?
2. What would be the total cost after discount if Anurag buys 5 items?
3. How much would Anurag save if he bought only 4 items?
4. What is the original total price of 5 items before the discount?
5. How much would Anurag save if the item price was ₹500 with a 25% discount?

**Tip**: Always round up when calculating the minimum number of items needed, as partial items are not possible in most real-world purchases.

One company is offering a 25% discount on a particular product. Anurag visited a store. He was trying to find a deal that would allow him to save at least Rs 390. How many minimum items should he purchase if each item costs Rs 340?

Learn how to calculate the minimum number of items Anurag needs to purchase to save at least Rs 390 with a 25% discount. This problem involves percentage discount calculation and solving inequalities. Suitable for students in Grades 6-8.

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