Math Problem Statement

Which of the following methods can be used to find the derivative of y = arcsin x with respect to x?

Solution

To determine which methods can be used to find the derivative of y=arcsinxy = \arcsin x with respect to xx, let’s examine each method proposed:

  1. Option I: Using the quotient rule to differentiate 1sinx\frac{1}{\sin x} is not applicable here. The function y=arcsinxy = \arcsin x does not involve 1sinx\frac{1}{\sin x}; it’s defined by the inverse sine function. Therefore, the quotient rule is unnecessary.

  2. Option II: Using the chain rule to differentiate sin(arcsinx)=x\sin(\arcsin x) = x is a valid approach. Since sin(arcsinx)=x\sin(\arcsin x) = x, differentiating both sides with respect to xx and applying the chain rule will yield the derivative of arcsinx\arcsin x.

  3. Option III: Using implicit differentiation on siny=x\sin y = x with respect to xx is also a valid approach. If y=arcsinxy = \arcsin x, then siny=x\sin y = x. By differentiating both sides with respect to xx, we can find dydx\frac{dy}{dx} using implicit differentiation.

Conclusion:

Only options II and III are valid methods. Therefore, the correct answer is:

C. II and III only

Would you like more details or have any questions on this solution?


Related Questions:

  1. How do you apply the chain rule in differentiating inverse trigonometric functions?
  2. What is implicit differentiation, and when is it useful?
  3. Can the quotient rule ever be applied in finding derivatives of inverse trigonometric functions?
  4. How would you differentiate y=arctanxy = \arctan x using implicit differentiation?
  5. How do we derive the general derivative formula for arcsinx\arcsin x?

Tip:

When differentiating functions involving inverse trigonometric functions, implicit differentiation often provides a straightforward solution.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Inverse Trigonometric Functions
Quotient Rule
Chain Rule
Implicit Differentiation

Formulas

y = arcsin(x)
d/dx [sin(arcsin(x))] = d/dx [x]
d/dx [sin(y) = x]

Theorems

Chain Rule for Differentiation
Implicit Differentiation

Suitable Grade Level

Grades 11-12