To find the class interval containing the median from the table, let's break it down step by step:

Step 1: Total frequency

We add up the frequencies to get the total number of flowers.

$16 + 16 + 2 + 13 + 3 + 20 = 70$

So, there are 70 flowers in total.

Step 2: Find the position of the median

The median is the middle value. Since there are 70 flowers, the median is the average of the 35th and 36th data points (because $\frac{70+1}{2} = 35.5$).

Step 3: Cumulative frequency

We calculate the cumulative frequency to determine in which class interval the 35th and 36th data points fall.

• For $40 < y \leq 50$: Cumulative frequency = 16
• For $50 < y \leq 60$: Cumulative frequency = 16 + 16 = 32
• For $60 < y \leq 70$: Cumulative frequency = 32 + 2 = 34
• For $70 < y \leq 80$: Cumulative frequency = 34 + 13 = 47
• For $80 < y \leq 90$: Cumulative frequency = 47 + 3 = 50
• For $90 < y \leq 100$: Cumulative frequency = 50 + 20 = 70

Step 4: Determine the class interval containing the median

The 35th and 36th data points fall in the interval $70 < y \leq 80$, because the cumulative frequency just before this is 34, and by the time we add the 13 data points in this class, the cumulative frequency becomes 47, which includes the 35th and 36th points.

Final Answer:

The class interval containing the median is $70 < y \leq 80$.

Would you like a detailed explanation of any step? Here are some related questions:

1. How do you calculate the exact median when the total number is odd?
2. Can you find the mode and mean from the same data?
3. How does cumulative frequency help in identifying the median?
4. What is the significance of the class interval when dealing with grouped data?
5. How would the process change if the data had different class widths?

Tip: Always double-check cumulative frequencies when dealing with grouped data for accurate median identification.