Math Problem Statement

Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected. Defects: 0, 1, 2, 3, 4, 5. Probability: 0.265, 0.292, 0.246, 0.141, 0.043, 0.013. (a) Find the mean, variance, and standard deviation of the probability distribution.

Solution

Let's break down the problem step by step to find the mean, variance, and standard deviation for the given probability distribution.

Given:

The number of defects per 1000 machine parts inspected:

  • Defects: 0, 1, 2, 3, 4, 5
  • Probability: 0.265, 0.292, 0.246, 0.141, 0.043, 0.013

Step 1: Calculate the Mean (Expected Value)

The mean (or expected value) μ\mu is calculated by the formula:

μ=xP(x)\mu = \sum x \cdot P(x)

Where xx is the number of defects, and P(x)P(x) is the corresponding probability.

So for this, we have:

μ=(0×0.265)+(1×0.292)+(2×0.246)+(3×0.141)+(4×0.043)+(5×0.013)\mu = (0 \times 0.265) + (1 \times 0.292) + (2 \times 0.246) + (3 \times 0.141) + (4 \times 0.043) + (5 \times 0.013)

Step 2: Calculate the Variance

The variance σ2\sigma^2 is calculated by the formula:

σ2=(xμ)2P(x)\sigma^2 = \sum (x - \mu)^2 \cdot P(x)

Step 3: Calculate the Standard Deviation

The standard deviation σ\sigma is simply the square root of the variance:

σ=σ2\sigma = \sqrt{\sigma^2}

I will now compute these values. Given data defects = [0, 1, 2, 3, 4, 5] probabilities = [0.265, 0.292, 0.246, 0.141, 0.043, 0.013]

Step 1: Calculate the mean (expected value)

mean = sum(x * p for x, p in zip(defects, probabilities))

Step 2: Calculate the variance

variance = sum((x - mean)**2 * p for x, p in zip(defects, probabilities))

Step 3: Calculate the standard deviation

std_deviation = variance**0.5

mean, variance, std_deviationThe results for the probability distribution are as follows:

  • Mean (Expected Value): 1.4 (rounded to one decimal place)
  • Variance: 1.47 (rounded to two decimal places)
  • Standard Deviation: 1.21 (rounded to two decimal places)

Would you like further details on these calculations, or do you have any questions?

Here are some related questions to deepen your understanding:

  1. How does the mean relate to the center of a probability distribution?
  2. How do you interpret the variance and standard deviation in the context of this problem?
  3. What is the significance of rounding in probability distributions?
  4. How can you calculate the expected value for continuous distributions?
  5. How would the mean and standard deviation change if the probabilities were altered?

Tip: When working with probability distributions, always double-check that the sum of the probabilities equals 1, as this ensures the distribution is valid!

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Math Problem Analysis

Mathematical Concepts

Probability Distribution
Expected Value
Variance
Standard Deviation

Formulas

\(\mu = \sum x \cdot P(x)\)
\(\sigma^2 = \sum (x - \mu)^2 \cdot P(x)\)
\(\sigma = \sqrt{\sigma^2}\)

Theorems

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Suitable Grade Level

Grades 9-12