Let's go step-by-step to solve your problem:

Part B: Calculate the mean, median, and mode of the ages.

Given ages:
$25, 28, 30, 35, 40, 42, 45, 50, 55, 60, 28, 32, 34, 37, 41, 43, 48, 52, 56, 60$

1. Mean:

The mean is calculated by adding all the values together and dividing by the number of values.

$\text{Mean} = \frac{\sum \text{Ages}}{\text{Number of Ages}}$

Let me calculate that.

2. Median:

The median is the middle value when the numbers are arranged in ascending order. If there is an even number of values, the median is the average of the two middle numbers.

Sorted Ages: $25, 28, 28, 30, 32, 34, 35, 37, 40, 41, 42, 43, 45, 48, 50, 52, 55, 56, 60, 60$

The total number of values is 20, so the median will be the average of the 10th and 11th values.

3. Mode:

The mode is the value that appears most frequently.

Now, let me calculate these values.### Part B Results:

1. Mean: 42.05
2. Median: 41.5
3. Mode: 28 and 60 (there are two modes as these values appear most frequently).

Part C: Standard Deviation

For computing the standard deviation using JMP, follow these steps:

1. Input the ages data into JMP.
2. Navigate to Analyze > Distribution.
3. Select the column containing the ages.
4. JMP will display the standard deviation along with other statistics in the output window.

Part D: Distribution Based on Mean, Median, and Mode

• Mean (42.05) and Median (41.5) are very close, suggesting the data is fairly symmetric.
• The presence of two modes (28 and 60) indicates a bimodal distribution, which could suggest there are two age groups that occur most frequently within the data (younger and older groups).

Thus, the distribution is roughly symmetric but with two distinct age peaks.

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Would you like more details on any part, or do you have any questions?

Here are 5 related questions to explore:

1. How does standard deviation reflect the spread of employee ages?
2. Can we classify this age distribution as skewed? Why or why not?
3. How would removing outliers affect the mean and median?
4. What does the presence of two modes imply about the employee demographics?
5. How could this data inform company decisions about employee benefits?

Tip: The median is often a better measure of central tendency when dealing with skewed data.