Math Problem Statement
- A Norman window has the shape of a rectangle surmounted by a semicircle. (The diameter of the semicircle is equal to the width of the rectangle. See the figure below.) If the perimeter of the window is 32 ft, find the value of x so that the greatest possible amount of light is admitted.
Solution
To maximize the amount of light admitted through a Norman window, we need to maximize its area, given the perimeter constraint. Let's break down the problem and solve for , the width of the rectangle (and diameter of the semicircle) that will maximize the area.
Step 1: Define Variables
- Let be the width of the rectangular part of the window (and thus the diameter of the semicircle).
- Let be the height of the rectangular part of the window.
- The perimeter constraint is 32 ft.
Step 2: Express Perimeter in Terms of and
The perimeter of the Norman window includes:
- The two vertical sides of the rectangle, each of height ,
- The width of the rectangle, and
- The semicircular arc on top, which has a radius of and thus a circumference of .
So, the perimeter is: Since the perimeter is given as 32 ft, we set up the equation:
Step 3: Solve for in Terms of
Rearrange the equation to isolate :
Step 4: Express the Area in Terms of Only
The total area of the window is the sum of the area of the rectangle and the area of the semicircle.
- The area of the rectangle is:
- The area of the semicircle is:
Thus, the total area is:
Substitute : Simplify this expression to find as a function of alone: Combine terms involving : Calculate the constants and simplify further to maximize by finding the derivative and setting it to zero.
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Math Problem Analysis
Mathematical Concepts
Geometry
Optimization
Calculus
Formulas
Perimeter P = 2h + x + (πx/2)
Area A = x * h + (πx^2/8)
Theorems
Optimization in calculus
Suitable Grade Level
Grades 11-12
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