Math Problem Statement

To prevent pests, an orchard can have no more than 9 times as many apple trees as peach trees. The number of apple trees plus 3 times the number of peach trees must not exceed 384. The revenue from a single apple tree is $88, and the revenue from a single peach tree is $106. What is the maximum revenue, and how many of each type of tree should be planted? Let x represent apple trees and y represent peach trees.

Solution

The problem states:

"To prevent pests, an orchard can have no more than 9 times as many apple trees as peach trees. Also, the number of apple trees plus 3 times the number of peach trees must not exceed 384. The revenue from a single apple tree is $88 and the revenue from a single peach tree is $106. Determine the number of each type of tree that will maximize revenue. What is the maximum revenue? Let x represent the number of apple trees and y represent the number of peach trees."

Step-by-Step Solution:

We are given the following:

  • x = number of apple trees.
  • y = number of peach trees.

Constraints:

  1. The number of apple trees cannot be more than 9 times the number of peach trees: x9yx \leq 9y

  2. The number of apple trees plus 3 times the number of peach trees must not exceed 384: x+3y384x + 3y \leq 384

Objective:

We want to maximize the total revenue, which is given by: Revenue=88x+106y\text{Revenue} = 88x + 106y

Steps:

1. Solve the constraints:

We have two inequalities:

  • x9yx \leq 9y
  • x+3y384x + 3y \leq 384

From x9yx \leq 9y, we know that xx must always be less than or equal to 9 times yy.

2. Maximize the objective function:

We need to maximize 88x+106y88x + 106y subject to the constraints.

Let’s first substitute xx from x9yx \leq 9y into the second constraint x+3y384x + 3y \leq 384.

If x=9yx = 9y, then: 9y+3y3849y + 3y \leq 384 12y38412y \leq 384 y38412=32y \leq \frac{384}{12} = 32

Thus, y32y \leq 32. The maximum number of peach trees is 32.

3. Find xx using the maximum yy:

If y=32y = 32, then x=9y=9×32=288x = 9y = 9 \times 32 = 288.

4. Calculate the maximum revenue:

Using x=288x = 288 and y=32y = 32, the total revenue is: Revenue=88×288+106×32\text{Revenue} = 88 \times 288 + 106 \times 32 Revenue=25344+3392=28736\text{Revenue} = 25344 + 3392 = 28736

Final Answer:

  • The number of apple trees, xx, is 288.
  • The number of peach trees, yy, is 32.
  • The maximum revenue is $28,736.

Would you like more details, or do you have any questions?

5 Related Questions:

  1. How would the solution change if the maximum ratio of apple trees to peach trees was 8 instead of 9?
  2. Can the same approach be applied to a different objective, such as minimizing costs instead of maximizing revenue?
  3. What happens if the revenue from a single apple tree decreases to $80?
  4. How would the problem be solved if the constraint on apple trees plus 3 times peach trees changed to a different equation?
  5. Can you explain the difference between maximizing a linear function and optimizing a nonlinear one?

Tip:

Always check if the constraints on a problem are linear, as this greatly simplifies finding the solution, often allowing you to use basic algebraic techniques or optimization methods like linear programming.

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Math Problem Analysis

Mathematical Concepts

Linear Programming
Optimization

Formulas

x ≤ 9y
x + 3y ≤ 384
Revenue = 88x + 106y

Theorems

Linear Programming Theorem

Suitable Grade Level

Grades 10-12