Math Problem Statement

The Bluebird Bakery sells more cookies when it lowers its prices, but this also changes profits. The profit function for the cookies is f(x) = -500(x - 0.45)^2 + 400. This function represents the profit earned when the price of a cookie is x dollars. The bakery wants to maximize its profits. The profit for selling cookies for $0.40 each and $0.75 each needs to be calculated.

Solution

The problem provides the profit function for the Bluebird Bakery, given by:

f(x)=500(x0.45)2+400f(x) = -500(x - 0.45)^2 + 400

This function models the profit in dollars, f(x)f(x), where xx represents the price of a cookie in dollars. We are asked to find the profit for two specific cookie prices: $0.40 and $0.75.

Step 1: Calculate the profit for selling cookies at $0.40 each

Substitute x=0.40x = 0.40 into the profit function:

f(0.40)=500(0.400.45)2+400f(0.40) = -500(0.40 - 0.45)^2 + 400 f(0.40)=500(0.05)2+400f(0.40) = -500(-0.05)^2 + 400 f(0.40)=500(0.0025)+400f(0.40) = -500(0.0025) + 400 f(0.40)=1.25+400=398.75f(0.40) = -1.25 + 400 = 398.75

Step 2: Calculate the profit for selling cookies at $0.75 each

Substitute x=0.75x = 0.75 into the profit function:

f(0.75)=500(0.750.45)2+400f(0.75) = -500(0.75 - 0.45)^2 + 400 f(0.75)=500(0.30)2+400f(0.75) = -500(0.30)^2 + 400 f(0.75)=500(0.09)+400f(0.75) = -500(0.09) + 400 f(0.75)=45+400=355f(0.75) = -45 + 400 = 355

Final Answers:

  • The profit for selling cookies for $0.40 each is $398.75.
  • The profit for selling cookies for $0.75 each is $355.00.

Would you like more details or have any other questions?

Here are five related questions you might explore:

  1. What is the maximum possible profit, and at what price does it occur?
  2. How would the profit change if the price of the cookies was increased to $1.00?
  3. What is the significance of the constant term 400 in the profit function?
  4. How does the negative coefficient 500-500 affect the shape of the profit function?
  5. Can you derive a general strategy for maximizing profit in this scenario?

Tip: The vertex form of a quadratic function, like the one here, makes it easy to identify the maximum or minimum point, which is useful in optimization problems.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Maximization in Algebra

Formulas

Profit function: f(x) = -500(x - 0.45)^2 + 400

Theorems

Vertex Form of a Quadratic Function

Suitable Grade Level

Grades 9-12