Math Problem Statement
Solution
To solve this problem, we aim to maximize the volume of a rectangular parallelepiped inscribed in a sphere using the method of Lagrange multipliers. Here’s the step-by-step solution:
Step 1: Problem setup
- Let the rectangular parallelepiped have dimensions , so its volume is:
- Since the parallelepiped is inscribed in a sphere, the constraint is that the distance from the origin to any corner of the parallelepiped lies on the sphere. This implies: where is the radius of the sphere.
Step 2: Lagrange multipliers
To maximize subject to , we solve: where and .
This leads to the system of equations:
- (constraint)
Step 3: Solve for
From the first three equations: Equating any two pairs:
- From , we get , so .
- From , we get , so .
Step 4: Substituting into the constraint
Assume (symmetry leads to a positive maximum):
Thus:
Step 5: Maximum volume
The maximum volume is:
Final Answer:
The maximum volume of the rectangular parallelepiped is:
Would you like further clarification on any step? Here are related questions for deeper exploration:
- Why does symmetry ensure for maximum volume in this case?
- How does the method of Lagrange multipliers guarantee optimal solutions under constraints?
- Can this method be adapted to maximize the volume of shapes inscribed in ellipsoids?
- How does the result change if the parallelepiped has specific fixed aspect ratios (e.g., )?
- What are practical applications of maximizing the volume of an object under constraints?
Tip: Always confirm your constraint and symmetry assumptions when solving geometry-based optimization problems!
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Math Problem Analysis
Mathematical Concepts
Optimization
Multivariable Calculus
Geometry
Formulas
Volume of rectangular parallelepiped: V = x * y * z
Constraint for a sphere: x^2 + y^2 + z^2 = R^2
Theorems
Lagrange Multipliers
Suitable Grade Level
Undergraduate Mathematics
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