A group of friends wants to go to the amusement park. They have no more than $250 to spend on parking and admission. Parking is $12.25, and tickets cost $22.25 per person, including tax. What is the maximum number of people who can go to the amusement park?


Let's define the problem mathematically:

- Parking cost: $12.25 (fixed)
- Admission ticket per person: $22.25 per person
- Total budget: $250

Let $ x $ represent the number of people who can go to the amusement park.

The total cost for parking and admission is given by:
\[
\text{Total Cost} = 12.25 + 22.25x
\]
We want the total cost to be less than or equal to $250:
\[
12.25 + 22.25x \leq 250
\]
Now, solve for $ x $.

### Step 1: Subtract the parking cost from the total budget
\[
22.25x \leq 250 - 12.25
\]
\[
22.25x \leq 237.75
\]

### Step 2: Divide by 22.25 to solve for $ x $
\[
x \leq \frac{237.75}{22.25}
\]
\[
x \leq 10.6876
\]

Since the number of people must be a whole number, round down to the nearest integer, which is 10.

### Conclusion:
The maximum number of people who can go to the amusement park is **10**.

Would you like more details or have any questions? Here are 5 related questions to expand on this:

1. What would happen if the ticket price increased by $1 per person?
2. How much would the group spend if only 8 people went?
3. What is the maximum number of people that can go if parking were free?
4. If the group had $300 instead of $250, how many people could go?
5. What is the total cost per person, including parking, if 9 people attend?

**Tip**: When solving real-life problems, always account for rounding where necessary, especially when dealing with people or items that can't be divided!

A group of friends wants to go to the amusement park. They have no more than $250 to spend on parking and admission. Parking is $12.25, and tickets cost $22.25 per person, including tax. What is the maximum number of people who can go to the amusement park?

Find out how to calculate the maximum number of people who can go to an amusement park with a budget of $250. This problem involves solving linear inequalities with costs for parking and ticket prices per person. Suitable for students in Grades 6-8.

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