Math Problem Statement

(1 point) Let b⃗ 1=[11] and b⃗ 2=[10]. The set B={b⃗ 1,b⃗ 2} is a basis for R2. Let T:R2→R2 be a linear transformation such that T(b⃗ 1)=8b⃗ 1+6b⃗ 2 and T(b⃗ 2)=7b⃗ 1+4b⃗ 2. (a) The matrix of T relative to the basis B is [T]B= ⎡⎣⎢⎢ ⎤⎦⎥⎥ . (b) The matrix of T relative to the standard basis E for R2 is [T]E= ⎡⎣⎢⎢ ⎤⎦⎥⎥

Solution

To solve this problem, we’ll start by constructing the matrix of the transformation TT relative to the basis BB (part (a)), and then use that to find the matrix of TT relative to the standard basis EE (part (b)).

Part (a): Matrix of TT relative to basis BB

Given:

  • b1=[11]b_1 = \begin{bmatrix} 1 \\ 1 \end{bmatrix}
  • b2=[10]b_2 = \begin{bmatrix} 1 \\ 0 \end{bmatrix}

The transformation TT is defined by:

  • T(b1)=8b1+6b2T(b_1) = 8b_1 + 6b_2
  • T(b2)=7b1+4b2T(b_2) = 7b_1 + 4b_2

In terms of the basis B={b1,b2}B = \{b_1, b_2\}, the images of b1b_1 and b2b_2 can be expressed as coordinate vectors relative to BB:

  • T(b1)=8b1+6b2T(b_1) = 8b_1 + 6b_2 corresponds to the vector [86]\begin{bmatrix} 8 \\ 6 \end{bmatrix} in the BB-basis.
  • T(b2)=7b1+4b2T(b_2) = 7b_1 + 4b_2 corresponds to the vector [74]\begin{bmatrix} 7 \\ 4 \end{bmatrix} in the BB-basis.

Thus, the matrix of TT relative to the basis BB is: [T]B=[8764][T]_B = \begin{bmatrix} 8 & 7 \\ 6 & 4 \end{bmatrix}

Part (b): Matrix of TT relative to the standard basis EE

To find the matrix of TT relative to the standard basis EE, we need to express T(b1)T(b_1) and T(b2)T(b_2) in terms of the standard basis vectors.

  1. Compute T(b1)T(b_1) and T(b2)T(b_2) in terms of the standard basis:

    • Since b1=[11]b_1 = \begin{bmatrix} 1 \\ 1 \end{bmatrix} and b2=[10]b_2 = \begin{bmatrix} 1 \\ 0 \end{bmatrix},
    • T(b1)=8b1+6b2=8[11]+6[10]=[8+68]=[148]T(b_1) = 8b_1 + 6b_2 = 8 \begin{bmatrix} 1 \\ 1 \end{bmatrix} + 6 \begin{bmatrix} 1 \\ 0 \end{bmatrix} = \begin{bmatrix} 8 + 6 \\ 8 \end{bmatrix} = \begin{bmatrix} 14 \\ 8 \end{bmatrix},
    • T(b2)=7b1+4b2=7[11]+4[10]=[7+47]=[117]T(b_2) = 7b_1 + 4b_2 = 7 \begin{bmatrix} 1 \\ 1 \end{bmatrix} + 4 \begin{bmatrix} 1 \\ 0 \end{bmatrix} = \begin{bmatrix} 7 + 4 \\ 7 \end{bmatrix} = \begin{bmatrix} 11 \\ 7 \end{bmatrix}.
  2. Construct [T]E[T]_E: Using these results, we have [T]E=[141187][T]_E = \begin{bmatrix} 14 & 11 \\ 8 & 7 \end{bmatrix}

Final Answer

  • (a) The matrix of TT relative to basis BB is: [T]B=[8764][T]_B = \begin{bmatrix} 8 & 7 \\ 6 & 4 \end{bmatrix}

  • (b) The matrix of TT relative to the standard basis EE is: [T]E=[141187][T]_E = \begin{bmatrix} 14 & 11 \\ 8 & 7 \end{bmatrix}

Would you like a more detailed breakdown or have any questions?


Here are five related questions to deepen understanding:

  1. How would the transformation matrix TT change if b1b_1 and b2b_2 were swapped in the basis BB?
  2. What does the transformation TT represent geometrically in R2\mathbb{R}^2?
  3. How would you find the eigenvalues and eigenvectors of TT with respect to the basis BB?
  4. How would you verify that BB is indeed a basis for R2\mathbb{R}^2?
  5. What is the determinant of [T]E[T]_E, and what does it tell you about TT?

Tip: When changing between different bases, understanding the relationship between basis vectors helps streamline transformation matrix calculations.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrices
Linear Transformation
Change of Basis

Formulas

T(b⃗ 1) = 8b⃗ 1 + 6b⃗ 2
T(b⃗ 2) = 7b⃗ 1 + 4b⃗ 2
[T]_B = [[8, 7], [6, 4]]
[T]_E = [[14, 11], [8, 7]]

Theorems

Transformation matrix relative to a basis
Change of basis formula

Suitable Grade Level

Undergraduate