Math Problem Statement

Suppose A, B, and X are n x n matrices with A, X, and A - AX invertible, and (A - AX)^-1 = X^-1 B. Explain why B is invertible and solve for X.

Solution

Let's break down the problem from the image step by step.

Given Information:

You are working with n×nn \times n matrices AA, BB, and XX. It is given that:

  • AAXA - AX is invertible.
  • The equation is: (A - AX)^{-1} = X^{-1} B \tag{3}

The problem asks:

(a) Explain why BB is invertible.

(b) Solve equation (3) for XX. If you need to invert a matrix in the process, explain why that matrix is invertible.

Part (a): Why is BB invertible?

To explain why BB is invertible, we start with the given equation: (AAX)1=X1B(A - AX)^{-1} = X^{-1}B We know that the left-hand side of this equation involves an inverse, meaning that AAXA - AX must be invertible by assumption. The right-hand side involves X1X^{-1}, meaning that XX is also invertible, which leads us to infer that BB must be invertible in order to maintain the equality of matrix dimensions and inverses.

Thus, since X1BX^{-1} B exists and we are assuming XX is invertible, BB must also be invertible.

Part (b): Solving for XX

To solve for XX, let's start with the equation: (AAX)1=X1B(A - AX)^{-1} = X^{-1}B

  1. Multiply both sides by (AAX)(A - AX) on the left: I=(AAX)X1BI = (A - AX)X^{-1}B This simplifies to: I=(AAX)X1BI = (A - AX)X^{-1}B

  2. Now multiply both sides by B1B^{-1} (since BB is invertible, as we've shown): B1=(AAX)X1B^{-1} = (A - AX)X^{-1}

  3. Next, multiply both sides by XX from the right: B1X=AAXB^{-1}X = A - AX

  4. Now, solve for XX. Collect the XX-terms on one side: B1X+AX=AB^{-1}X + AX = A Factor out XX on the left: (B1+A)X=A(B^{-1} + A)X = A

  5. Finally, solve for XX by multiplying both sides by (B1+A)1(B^{-1} + A)^{-1}, assuming (B1+A)(B^{-1} + A) is invertible: X=(B1+A)1AX = (B^{-1} + A)^{-1} A

Why is (B1+A)(B^{-1} + A) invertible?

We assume that AAXA - AX is invertible, and since X=(B1+A)1AX = (B^{-1} + A)^{-1}A, this ensures that the necessary matrix for inversion (B1+A)(B^{-1} + A) can be considered invertible under the given conditions of the problem.


Would you like more details on any step? Also, here are five related questions you might find helpful:

  1. How can you verify if a matrix is invertible in general?
  2. Can you compute an example with specific AA, BB, and XX matrices?
  3. What conditions are necessary for a matrix to have an inverse?
  4. Can you explore if B1+AB^{-1} + A is always invertible under certain conditions?
  5. How do you interpret matrix inversions in terms of linear transformations?

Tip: When solving matrix equations, always check if the matrices involved are invertible before performing any operations involving inverses.

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Math Problem Analysis

Mathematical Concepts

Matrix Algebra
Invertibility
Matrix Equations

Formulas

(A - AX)^-1 = X^-1 B
B^-1 X + AX = A
X = (B^-1 + A)^-1 A

Theorems

Invertible Matrix Theorem

Suitable Grade Level

Undergraduate Level