Math Problem Statement
Solution
Let's work through the problems one by one:
Exercise 2.4.9: In each case, either prove the assertion or give an example showing that it is false.
a. If is a square matrix, then is invertible.
False. A square matrix being non-zero does not guarantee invertibility. For example, consider the matrix: This is a square matrix, and it is not the zero matrix, but it is not invertible because its determinant is 0 (a requirement for invertibility is that the determinant must be non-zero).
b. If and are both invertible, then is invertible.
False. The sum of two invertible matrices is not always invertible. Consider the following counterexample: Both and are invertible, but: The resulting matrix is the zero matrix, which is not invertible.
c. If and are both invertible, then is invertible.
True. If both and are invertible, then their product is also invertible. We know that: Both and are invertible since the transpose of an invertible matrix is also invertible. Therefore, the transpose is invertible.
d. If , then is invertible.
True. If , then: So, is a scalar multiple of the identity matrix, meaning that must be invertible (since we can multiply by and still have a valid inverse matrix).
e. If and , then is invertible.
False. This statement is generally false. Consider the matrix: Clearly: and . However, is not invertible because its determinant is 0.
Do you want more details or have any further questions?
Here are five related questions to expand your understanding:
- What are the conditions for a matrix to be invertible?
- Can the sum of more than two invertible matrices be invertible?
- How does the property of the transpose affect invertibility?
- Can a matrix with non-zero determinant always be invertible?
- How does the rank of a matrix relate to its invertibility?
Tip: Always check the determinant of a matrix when determining if it is invertible!
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Linear Algebra
Matrix Inverses
Determinants
Matrix Transpose
Formulas
A matrix A is invertible if det(A) ≠ 0.
For matrices A and B, (A⁻¹B)ᵀ = Bᵀ(A⁻¹)ᵀ.
If A⁴ = 3I, then A is invertible because A^4 can be reduced to a scalar multiple of the identity matrix.
Theorems
Invertibility criterion: A matrix is invertible if its determinant is non-zero.
The transpose of an invertible matrix is also invertible.
Suitable Grade Level
University Level (Linear Algebra)