To solve for A9x, we can leverage the fact that A is a diagonalizable matrix. Given the eigenvectors v1β and v2β, and their corresponding eigenvalues Ξ»1β and Ξ»2β, the matrix A can be represented as:
A=PDPβ1
where P is the matrix of eigenvectors and D is the diagonal matrix of eigenvalues.
Given:
- Eigenvectors: v1β=(1β1β) and v2β=(11β)
- Eigenvalues: Ξ»1β=21β and Ξ»2β=2
- Vector x=(5β1β)
- Construct the matrix P and D:
P=(1β1β11β),D=(21β0β02β)
- Find the inverse of P:
Pβ1=21β(11ββ11β)
- Compute A9:
Since A=PDPβ1, then A9=PD9Pβ1.
D9=((21β)90β029β)=(5121β0β0512β)
A9=P(5121β0β0512β)Pβ1
- Calculate A9x:
A9x=PD9Pβ1x
First, find Pβ1x:
Pβ1x=21β(11ββ11β)(5β1β)=21β(5β(β1)5+(β1)β)=21β(64β)=(32β)
Then, multiply by D9:
D9(32β)=(5121β0β0512β)(32β)=(5123β1024β)
Finally, multiply by P:
A9x=(1β1β11β)(5123β1024β)=(5123β+1024β5123β+1024β)=(1024.0058593751023.994140625β)
So,
A9xβ(1024.011023.99β)
Would you like more details on any part of this process?
Related Questions:
- How do you diagonalize a matrix?
- What are the properties of eigenvalues and eigenvectors in matrix multiplication?
- How do you compute matrix powers using eigenvalues and eigenvectors?
- What are some practical applications of diagonalization in engineering?
- How can one find the inverse of a 2x2 matrix quickly?
Tip:
When dealing with matrix exponentiation, diagonalization is a powerful tool that simplifies the computation, especially for high powers.