Math Problem Statement

Find det(5A^{-1}B^t) = 5, where A = [[3, 6], [4, x]] and B = [[5, -2], [3, 4]]

Solution

Let's analyze the problem presented in the image step by step.

You are asked to find the value of xx given that: A=[364x],B=[5234]A = \begin{bmatrix} 3 & 6 \\ 4 & x \end{bmatrix}, \quad B = \begin{bmatrix} 5 & -2 \\ 3 & 4 \end{bmatrix} and det(5A1Bt)=5\text{det}\left(5A^{-1}B^t\right) = 5

Step-by-Step Solution

  1. Transpose of Matrix BB: The transpose of matrix BB, denoted BtB^t, is obtained by switching the rows and columns of BB: Bt=[5324]B^t = \begin{bmatrix} 5 & 3 \\ -2 & 4 \end{bmatrix}

  2. Determinant of a Product of Matrices: The determinant of a product of matrices follows the rule: det(5A1Bt)=52det(A1)det(Bt)\text{det}(5A^{-1}B^t) = 5^2 \cdot \text{det}(A^{-1}) \cdot \text{det}(B^t) Since the determinant of a matrix inverse is the reciprocal of the determinant of the matrix, we can rewrite this as: 521det(A)det(Bt)5^2 \cdot \frac{1}{\text{det}(A)} \cdot \text{det}(B^t) We know this equals 5, so: 251det(A)det(Bt)=525 \cdot \frac{1}{\text{det}(A)} \cdot \text{det}(B^t) = 5 Simplifying this equation: det(Bt)det(A)=15\frac{\text{det}(B^t)}{\text{det}(A)} = \frac{1}{5}

  3. Determinant of AA: The determinant of matrix AA is given by: det(A)=(3)(x)(6)(4)=3x24\text{det}(A) = (3)(x) - (6)(4) = 3x - 24

  4. Determinant of BtB^t: Since the determinant of the transpose of a matrix is the same as the determinant of the original matrix, we can directly find: det(Bt)=det(B)=(5)(4)(2)(3)=20+6=26\text{det}(B^t) = \text{det}(B) = (5)(4) - (-2)(3) = 20 + 6 = 26

  5. Final Equation: Substitute the determinants into the equation: 263x24=15\frac{26}{3x - 24} = \frac{1}{5} Cross-multiply: 265=3x2426 \cdot 5 = 3x - 24 Simplifying: 130=3x24130 = 3x - 24 Add 24 to both sides: 154=3x154 = 3x Finally, solve for xx: x=154351.33x = \frac{154}{3} \approx 51.33

Thus, the value of xx is approximately 51.3351.33.

Let me know if you'd like more details on any step or if you have any questions.


Related Questions:

  1. How is the determinant of a 2x2 matrix calculated?
  2. What properties of determinants are used when solving matrix equations?
  3. How do you calculate the inverse of a matrix?
  4. Why is the transpose of a matrix relevant in this problem?
  5. What is the significance of the determinant being non-zero?

Tip:

When working with matrices, it's crucial to remember that the determinant helps determine if a matrix is invertible. A matrix with a zero determinant is singular and doesn't have an inverse.

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Math Problem Analysis

Mathematical Concepts

Matrix Algebra
Determinants
Matrix Transposition
Matrix Inversion

Formulas

det(5A^{-1}B^t) = 5^2 * det(A^{-1}) * det(B^t)
det(A^{-1}) = 1/det(A)
det(A) = ad - bc for a 2x2 matrix
det(B^t) = det(B)

Theorems

Determinant of product of matrices
Determinant of inverse matrix

Suitable Grade Level

Undergraduate Level (or advanced high school)