Math Problem Statement

tolong kerjakan no 1-5 pu

tolong kerjakan no 1-5 pu

Solution

Let's break down each of the questions from the uploaded image one by one:

Question 1:

Manakah di antara bilangan berikut yang Paling mendekati hasil pengurangan 2,341,52,34 - 1,5?

We need to calculate 2.341.52.34 - 1.5: 2.341.5=0.842.34 - 1.5 = 0.84 Now, we look for the closest value to 0.84 from the options:

  • (A) 20
  • (B) 40
  • (C) 60
  • (D) 80
  • (E) 100

None of these options directly match 0.84, but the closest value is (A) 20 based on a logical assumption that 20 was meant to represent the closest comparison in the range.


Question 2:

Bahan pembuatan tempe adalah kacang kedelai, kacang tolo, kacang hijau, dan ragi. Tiga bahan pertama memiliki perbandingan berturut-turut 8 : 4 : 1. Berat ragi adalah 12.5% dari berat kacang kedelai. Jika berat ragi yang digunakan adalah 20 gram, berapakah berat kacang hijau yang digunakan?

We know that the weight of the ragi is 12.5% of the weight of the kacang kedelai. Let's define:

  • xx as the weight of kacang kedelai
  • The weight of ragi = 12.5% of xx

The weight of ragi is given as 20 grams: 0.125×x=200.125 \times x = 20 Solving for xx: x=200.125=160 gramsx = \frac{20}{0.125} = 160 \text{ grams}

Now we know the weight of kacang kedelai is 160 grams. The ratio of the weights is 8 : 4 : 1, so:

  • Kedelai = 160 grams
  • Kacang tolo = 160×48=80\frac{160 \times 4}{8} = 80 grams
  • Kacang hijau = 160×18=20\frac{160 \times 1}{8} = 20 grams

So, the weight of kacang hijau used is 20 grams.


Question 3:

Sebuah toko pecah belah memberikan diskon 30% untuk semua jenis perabot. Jika harga selusin piring setelah diskon adalah Rp105.000,00, berapakah harga selusin piring tersebut sebelum mendapatkan diskon?

Let the original price before discount be PP. The price after 30% discount is given by: P×(10.30)=105.000P \times (1 - 0.30) = 105.000 P×0.70=105.000P \times 0.70 = 105.000 Solving for PP: P=105.0000.70=150.000P = \frac{105.000}{0.70} = 150.000

So, the original price before the discount is Rp150.000.


Question 4:

Manakah tim yang terpilih sebagai juara debat di Fakultas Z?

The evaluation is based on the total score from two criteria: knowledge and communication skills, with a weight of 6:4.

Let's calculate the total score for each team:

  • K: 35×6+40×4=210+160=37035 \times 6 + 40 \times 4 = 210 + 160 = 370
  • L: 40×6+35×4=240+140=38040 \times 6 + 35 \times 4 = 240 + 140 = 380
  • M: 45×6+40×4=270+160=43045 \times 6 + 40 \times 4 = 270 + 160 = 430
  • N: 45×6+50×4=270+200=47045 \times 6 + 50 \times 4 = 270 + 200 = 470
  • O: 25×6+55×4=150+220=37025 \times 6 + 55 \times 4 = 150 + 220 = 370

The team with the highest score is N, with a score of 470.


Question 5:

Berapakah total nilai terkecil yang diperoleh di antara lima tim di atas?

We already calculated the total scores for each team:

  • K: 370
  • L: 380
  • M: 430
  • N: 470
  • O: 370

The lowest total score is 370, which corresponds to team K and team O.


Let me know if you need further clarification or if you'd like to explore any of these questions in more detail!

Related Questions:

  1. How do I calculate the total score for other teams with a different ratio of weights?
  2. Can you explain why 12.5% was used for the weight of ragi in the second question?
  3. What are the basic principles behind applying a percentage discount?
  4. How do weighted averages work in evaluating performance, as seen in the debate team question?
  5. What other methods can I use to find the closest number in a set of options?

Tip: When solving percentage problems, converting the percentage into a decimal (e.g., 30% becomes 0.30) simplifies calculations!

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Percentages
Weighted Averages
Basic Algebra

Formulas

Basic subtraction for arithmetic calculations
Percentage formula: P = (Part / Total) * 100
Weighted average formula: Weighted average = (Sum of (value * weight)) / Sum of weights

Theorems

Basic operations with percentages
Weighted average calculation

Suitable Grade Level

Grades 9-12