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Let's begin solving the math problems from the image you provided.

### Problem 1:
\( 22 \div 2 \times 3 - 12 \div 3 \times 2 = ? \)

**Solution:**
We solve this using the order of operations (BODMAS/PEMDAS):
- First, division and multiplication from left to right.

\[
22 \div 2 = 11, \quad 12 \div 3 = 4
\]
So, we now have:
\[
11 \times 3 - 4 \times 2
\]
Next, solve multiplication:
\[
11 \times 3 = 33, \quad 4 \times 2 = 8
\]
Now subtract:
\[
33 - 8 = 25
\]
Thus, the answer is **25**.

---

### Problem 2:
#### (a) How many degrees is \( 25 \% \) of \( 360 \degree \)?
**Solution:**
\[
25\% \times 360 = \frac{25}{100} \times 360 = 90 \degree
\]
Thus, the answer is **90 degrees**.

#### (b) What is \( 0.4 \times 0.05 \)?
**Solution:**
\[
0.4 \times 0.05 = 0.02
\]
Thus, the answer is **0.02**.

---

### Problem 3:
Find the third term of the sequence \( 1, 3, 9, 11, 13 \).

**Solution:**
The third term is simply **9**.

---

### Problem 4:
Calculate \( 6^x = 2^x \times 7^x \), solve for \( x \).

**Solution:**
We simplify the equation:
\[
6^x = (2 \times 7)^x
\]
This implies \( 6^x = 14^x \), which is only possible if \( x = 0 \).

Thus, the answer is **x = 0**.

---

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