The uploaded image contains mathematical exercises written in Vietnamese. I'll transcribe and explain the problem set step by step, then solve it.

Transcription of the Questions:

1. Perform the calculations (simplify if possible):

(a) $-32.56 - 32.25 - 32.19$

(b) $\frac{9^3 \cdot 25^3}{18^2 \cdot 125^2}$

(c) $\frac{(3 \cdot 4 \cdot 2^{16})^2}{11 \cdot 12^{13} \cdot 4^{11} \cdot 16^9}$

(d) $\frac{5 \cdot 4^{15} \cdot 9 - 4 \cdot 3^{20} \cdot 8^9}{5 \cdot 2^9 \cdot 6^{19} - 7 \cdot 2^{29} \cdot 27^6}$

(e) $\frac{151515}{161616} + \frac{17^9}{12^{10}} - \frac{1500}{1600} - \frac{1616}{1717}$

2. Compare $A$ and $B$:

• $A = 1 + 2012 + 2012^2 + \dots + 2012^{72}$
• $B = 2012^{73} - 1$

3. Compare $E$ and $Q$:

• $E = \frac{2018^{99} - 1}{2018^{100} - 1}$
• $Q = \frac{2018^{98} - 1}{2018^{99} - 1}$

4. Find all prime numbers $p$ such that $p + 8$ and $p + 10$ are also primes.

Solutions:

1. Perform the calculations:

(a) $-32.56 - 32.25 - 32.19 = -(32.56 + 32.25 + 32.19) = -96.99$

(b) Simplify the fractions: