Math Problem Statement
solve problem 2 and explain the steps
Solution
To solve Problem 2, let's analyze the system:
The equation of motion for the mass-spring-damper system is given as:
Where:
- (mass),
- (damping coefficient),
- (spring constant),
- (initial displacement),
- (initial velocity).
Step 1: Characteristic Equation
The characteristic equation is obtained by substituting into the differential equation:
Substitute , , and :
Factorize the equation:
So, (repeated root).
Step 2: General Solution
For a repeated root , the general solution of the differential equation is:
Substitute :
Step 3: Apply Initial Conditions
- Initial Condition 1: :
Substitute into :
So, .
- Initial Condition 2: :
Differentiate :
At :
Substitute :
Step 4: Final Solution
Substitute and into :
This is the motion of the system.
Explanation of Steps
- Derived the characteristic equation from the differential equation.
- Solved for the roots of the characteristic equation, which are repeated.
- Constructed the general solution for a repeated root.
- Used the initial conditions to find the constants and .
- Substituted the constants back into the general solution to obtain the final expression.
Would you like a graph of this solution or further explanation?
Related Questions
- How does the damping coefficient affect the solution for different values?
- What happens if the roots of the characteristic equation are complex instead of repeated?
- How would the solution change if the initial velocity were not zero?
- What is the significance of the exponential decay factor ?
- How would you analyze the system if external forces were acting on it?
Tip
For repeated roots, always check if your solution includes both terms and , as the
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Math Problem Analysis
Mathematical Concepts
Differential equations
Mass-spring-damper system
Damped harmonic motion
Formulas
m * x'' + b * x' + k * x = 0
Characteristic equation: m * λ^2 + b * λ + k = 0
Theorems
Solution for second-order linear differential equations
Behavior of repeated roots in characteristic equations
Suitable Grade Level
Undergraduate level (Mechanical/Electrical Engineering)
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