Math Problem Statement

give me answer

Find the missing quantities. Round rates to the nearest whole percent and money to the nearest cent.

Solution

Let's break down the problem:

We are given:

  • % Markdown = 43%
  • $ Markdown = $2.46
  • We need to find the Original Price and Reduced Price.

Step 1: Understanding the relationship

The markdown amount ($2.46) represents 43% of the original price.

This means: Markdown amount=Original price×Markdown percentage100\text{Markdown amount} = \text{Original price} \times \frac{\text{Markdown percentage}}{100} 2.46=Original price×431002.46 = \text{Original price} \times \frac{43}{100} Solving for the Original price:

Original price=2.460.435.72\text{Original price} = \frac{2.46}{0.43} \approx 5.72

Step 2: Finding the reduced price

The reduced price is the original price minus the markdown amount:

Reduced price=5.722.46=3.26\text{Reduced price} = 5.72 - 2.46 = 3.26

Conclusion:

  • Original price ≈ $5.72
  • Reduced price ≈ $3.26

Therefore, the correct answer is Option D: Original price = $5.72, Reduced price = $3.26.

Would you like more details or have any questions?

Here are some related questions for further practice:

  1. How would you calculate the markdown percentage if you were given the original price and reduced price?
  2. If the markdown was 50%, what would the reduced price be for an item that costs $10 originally?
  3. How can you determine the original price if you're given only the reduced price and the markdown percentage?
  4. If the markdown is $5 and the percentage is 20%, what is the original price?
  5. Can the markdown percentage ever be more than 100%?

Tip: Always check that the markdown amount aligns with the percentage reduction before finalizing your answer.

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Math Problem Analysis

Mathematical Concepts

Percentages
Markdown Calculation
Algebra

Formulas

Markdown amount = Original price × (Markdown percentage / 100)
Original price = Markdown amount / (Markdown percentage / 100)
Reduced price = Original price - Markdown amount

Theorems

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Suitable Grade Level

Grades 6-8