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To solve this problem, let's break it down step by step.

We know:
- The percent markdown is 43%.
- The dollar markdown is $2.46.

The reduced price (after the markdown) can be found using the formula:
\[
\text{Reduced Price} = \text{Original Price} - \text{Markdown}
\]
Alternatively, if we know the percentage markdown, we can express the markdown as:
\[
\text{Markdown} = (\text{Percent Markdown}) \times \text{Original Price}
\]

Let $ p $ represent the original price.

From the table:
\[
43\% \text{ of } p = 2.46
\]
So:
\[
0.43 \times p = 2.46
\]

To solve for $ p $ (the original price), divide both sides by 0.43:
\[
p = \frac{2.46}{0.43} \approx 5.72
\]

Thus, the original price is approximately $5.72.

Now, to find the reduced price:
\[
\text{Reduced Price} = 5.72 - 2.46 = 3.26
\]

The correct option would therefore be:
**D. Original price = $5.72 | Reduced price = $3.26**

Would you like more details on the process, or any clarifications? 

Here are some related questions:
1. How would the result change if the markdown percentage were 50%?
2. Can you calculate the markdown if the original price were $10 and the reduced price was $6?
3. What would be the new reduced price if the markdown was increased by $1?
4. How do you calculate the percentage markdown from the original price and reduced price?
5. What happens to the reduced price if the original price is doubled but the dollar markdown remains the same?

**Tip:** When solving percentage problems, it helps to convert percentages into decimals by dividing by 100 before multiplying with the original value!

Find the missing quantities. Round rates to the nearest whole percent and money to the nearest cent. Given a 43% markdown and a $2.46 markdown, calculate the original price and reduced price.

Learn how to calculate the original price and reduced price based on a 43% markdown and a $2.46 reduction. This problem involves discount percentage, basic algebra, and arithmetic, and is suitable for Grades 7-9.

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