From the image you provided, I see that you're solving parts of a statistics problem.

• Part (c) asks for the standard error, and it's given as 1.1622.
• Part (d) asks to find the margin of error, rounding to two decimal places.

The margin of error (ME) is calculated using the formula:

$\text{Margin of Error} = \text{Critical Value} \times \text{Standard Error}$

From part (c), the standard error is 1.1622, and from the previous part, the critical value is 1.645.

Let's calculate it:

$\text{Margin of Error} = 1.645 \times 1.1622 = 1.911 \, (\text{rounded to two decimal places})$

Thus, the margin of error is 1.91.

Would you like more details or have any other questions? Here are some related questions for deeper understanding:

1. What does the margin of error represent in a confidence interval?
2. How would the margin of error change if the critical value were higher?
3. What would happen to the margin of error if the sample size increased?
4. Can you explain the difference between margin of error and standard error?
5. How is the critical value determined for different confidence levels?

Tip: A larger sample size reduces the standard error, which in turn lowers the margin of error, providing a more precise estimate.