The margin of error (ME) at a 95% confidence level can be calculated using the formula:

$ME = Z \cdot SE$

Where:

• $Z$ is the z-score corresponding to the 95% confidence level.
• $SE$ is the standard error.

For a 95% confidence level, the z-score ($Z$) is approximately 1.96.

Given:

• $SE = 4.1$

$ME = 1.96 \cdot 4.1 = 8.036$

Margin of Error = 8.04 (rounded to two decimal places).

Would you like further details or have additional questions?

Here are 5 related questions for deeper understanding:

1. What is the formula for calculating the standard error?
2. How does changing the confidence level affect the margin of error?
3. Why is the z-score used in margin of error calculations?
4. What is the relationship between sample size and the standard error?
5. How can margin of error help interpret confidence intervals?

Tip: Always verify the confidence level to use the appropriate z-score for accuracy!