Math Problem Statement

Jada is looking at a map of a square park that has a scale of 5 centimeters to 200 feet. Jada lives 500 feet from the park. How long would this distance be on the map? If Jada ran around the perimeter of the park once, what distance would she run? How many times would she need to run around the park to complete a mile (5280 feet)?

Solution

Let's solve the problems based on the images you've uploaded.


Image 1 (Problem 5)

  • Scale: 5 centimeters (cm) on the map represents 200 feet in real life.
  • Question: Jada lives 500 feet from the park. How long would this distance be on the map?

Solution:

We can use the given scale ratio to convert real-life distance to the map distance.

  1. Scale ratio: 5cm200ft\frac{5 \, \text{cm}}{200 \, \text{ft}}
  2. Real distance: 500 feet

Set up a proportion: 5cm200ft=xcm500ft\frac{5 \, \text{cm}}{200 \, \text{ft}} = \frac{x \, \text{cm}}{500 \, \text{ft}}

Solving for xx: x=5×500200=2500200=12.5cmx = \frac{5 \times 500}{200} = \frac{2500}{200} = 12.5 \, \text{cm}

Thus, the distance from Jada's house to the park would be 12.5 cm on the map.


Image 2 (Problems 6-7)

  • Map dimensions: Each side of the park on the map is 10 cm.
  • Scale: 5 cm = 200 feet in real life.
  • Question 6: If Jada ran around the perimeter of the park, what distance would she run?

Solution:

Since the park is square-shaped and each side on the map is 10 cm:

  1. Perimeter of the park on the map: 4×10=40cm4 \times 10 = 40 \, \text{cm}
  2. Convert map distance to real distance:

Using the scale 5cm200ft\frac{5 \, \text{cm}}{200 \, \text{ft}}, we convert 40 cm:

5cm200ft=40cmxft\frac{5 \, \text{cm}}{200 \, \text{ft}} = \frac{40 \, \text{cm}}{x \, \text{ft}} x=40×2005=1600feetx = \frac{40 \times 200}{5} = 1600 \, \text{feet}

Thus, Jada would run 1600 feet around the park.


Question 7: How many times would Jada need to run around the park to complete a mile (5280 feet)?

Solution:

  1. Distance per lap: 1600 feet (from previous calculation).
  2. Total distance for 1 mile: 5280 feet.

Set up a proportion: 5280ft1600ft=3.3\frac{5280 \, \text{ft}}{1600 \, \text{ft}} = 3.3

Thus, Jada would need to run approximately 3.3 laps to complete a mile.


Do you have any questions or need further details? Here are 5 related questions you can explore:

  1. How can we calculate the area of the park in real life based on the given map?
  2. If Jada increases her running distance by 25%, how many laps would she need to run?
  3. What would the perimeter of the park be if the map scale changed to 1 cm = 100 feet?
  4. How would the map distance change if Jada lived 1000 feet from the park?
  5. How long would it take Jada to complete 3.3 laps if she runs at 6 feet per second?

Tip: Always set up proportions carefully when working with different units of measurement.

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Math Problem Analysis

Mathematical Concepts

Proportions
Ratios
Scale conversions
Perimeter calculation

Formulas

Proportion formula: a/b = c/d
Perimeter of a square: P = 4s

Theorems

Proportion Theorem

Suitable Grade Level

Grades 6-8