Math Problem Statement
Solution
Let's solve the problems based on the images you've uploaded.
Image 1 (Problem 5)
- Scale: 5 centimeters (cm) on the map represents 200 feet in real life.
- Question: Jada lives 500 feet from the park. How long would this distance be on the map?
Solution:
We can use the given scale ratio to convert real-life distance to the map distance.
- Scale ratio:
- Real distance: 500 feet
Set up a proportion:
Solving for :
Thus, the distance from Jada's house to the park would be 12.5 cm on the map.
Image 2 (Problems 6-7)
- Map dimensions: Each side of the park on the map is 10 cm.
- Scale: 5 cm = 200 feet in real life.
- Question 6: If Jada ran around the perimeter of the park, what distance would she run?
Solution:
Since the park is square-shaped and each side on the map is 10 cm:
- Perimeter of the park on the map:
- Convert map distance to real distance:
Using the scale , we convert 40 cm:
Thus, Jada would run 1600 feet around the park.
Question 7: How many times would Jada need to run around the park to complete a mile (5280 feet)?
Solution:
- Distance per lap: 1600 feet (from previous calculation).
- Total distance for 1 mile: 5280 feet.
Set up a proportion:
Thus, Jada would need to run approximately 3.3 laps to complete a mile.
Do you have any questions or need further details? Here are 5 related questions you can explore:
- How can we calculate the area of the park in real life based on the given map?
- If Jada increases her running distance by 25%, how many laps would she need to run?
- What would the perimeter of the park be if the map scale changed to 1 cm = 100 feet?
- How would the map distance change if Jada lived 1000 feet from the park?
- How long would it take Jada to complete 3.3 laps if she runs at 6 feet per second?
Tip: Always set up proportions carefully when working with different units of measurement.
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Math Problem Analysis
Mathematical Concepts
Proportions
Ratios
Scale conversions
Perimeter calculation
Formulas
Proportion formula: a/b = c/d
Perimeter of a square: P = 4s
Theorems
Proportion Theorem
Suitable Grade Level
Grades 6-8