To solve the problem, we are given the following information:

• The scale of the drawing is $1 \, \text{cm} = 60 \, \text{m}$.
• The dimensions of the rectangular park in the drawing are $11.6 \, \text{cm}$ by $5.9 \, \text{cm}$.

Step 1: Convert the drawing dimensions to actual dimensions.

Using the given scale, we multiply the drawing dimensions by 60 to convert them into meters.

• Actual length = $11.6 \, \text{cm} \times 60 = 696 \, \text{m}$
• Actual width = $5.9 \, \text{cm} \times 60 = 354 \, \text{m}$

Step 2: Calculate the perimeter of the park.

The perimeter $P$ of a rectangle is given by the formula:

$P = 2 \times (\text{length} + \text{width})$

Substituting the actual length and width:

$P = 2 \times (696 \, \text{m} + 354 \, \text{m}) = 2 \times 1050 \, \text{m} = 2100 \, \text{m}$

Final Answer:

The actual perimeter of the park is $2100 \, \text{m}$.

Would you like more details or have any questions?

Here are five related questions:

1. How would the perimeter change if the scale was 1 cm = 100 m instead?
2. What would be the area of the park in square meters?
3. If the park had a walking path along the perimeter, how many laps would make 5 km?
4. What is the relationship between the drawing’s dimensions and the actual dimensions?
5. How would the problem change if the park had different shapes?

Tip: When working with scale drawings, always ensure to adjust both dimensions before performing any calculations involving perimeter or area.