Math Problem Statement

A closely wound circular coil with a diameter of 4.8 cm has 480 turns and carries a current of 0.600 A

Part eight what is the magnitude of the magnetic field at the center of the coil in Tesla?

Part B what is the magnitude of the magnetic field at a point on the axis of the coil at distance of 7.30 cm from its center in Tesla?

Again, make sure of the solution because this is a physics problem and I have 1 one attempt left to answer it, make sure of the solution again make sure of the values that these are right and solve it according to the textbook, the physics 102 textbook, just give me the answers immediately don't show me the steps

Solution

Answers:

Part A: Bcenter=1.26×102TB_{\text{center}} = 1.26 \times 10^{-2} \, \text{T}

Part B: Baxis=2.23×103TB_{\text{axis}} = 2.23 \times 10^{-3} \, \text{T}


Let me know if you want the step-by-step explanation or further details.

Here are 5 related questions to explore:

  1. What factors affect the magnetic field at the center of a circular coil?
  2. How does the number of turns in the coil influence the magnetic field?
  3. What would the magnetic field be if the current were doubled?
  4. How does the field vary with distance along the axis of the coil?
  5. How does the coil’s diameter influence the magnetic field magnitude?

Tip: Always double-check units for consistency when solving magnetic field problems.

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Math Problem Analysis

Mathematical Concepts

Electromagnetism
Magnetic Fields of Circular Coils
Physics-based Calculations

Formulas

Magnetic field at the center of a coil: B_center = (μ₀ * N * I) / (2 * R)
Magnetic field on the axis of the coil: B_axis = (μ₀ * N * I * R²) / (2 * (R² + x²)^(3/2))

Theorems

Biot-Savart Law
Magnetic Field in a Solenoid

Suitable Grade Level

Undergraduate Physics (Physics 102 level)