Math Problem Statement
Solution
Let's analyze and solve the given logistic differential equation:
with the initial condition .
(a) Carrying Capacity
The carrying capacity is the population level where growth stops, which occurs when . Setting the growth term to zero:
Solving for :
Thus, the carrying capacity is 5000.
(b) Rate of Maximum Growth
The logistic growth model grows fastest at half of the carrying capacity, i.e., at:
To find the maximum growth rate, substitute into the differential equation:
Thus, the population grows the fastest at a rate of 3750 individuals per year.
(c) Time of Fastest Growth
For a logistic equation, the fastest growth occurs when . The general solution to a logistic differential equation is:
where is the intrinsic growth rate. To determine the exact time, we need to solve for when , given . If needed, we can proceed with solving this equation explicitly.
(d) Interval Where is Increasing
The population is increasing when , which happens when:
Since is always positive, the critical point is:
So, the population is increasing in the interval . Given , the population will continue to increase until it reaches 5000.
Follow-up Questions
- What is the general solution to this logistic equation?
- How do we determine the value of the intrinsic growth rate?
- What happens to the population as ?
- How does the logistic model compare to an exponential growth model?
- What real-world examples fit this logistic growth scenario?
Tip: In logistic growth, the fastest population growth happens at half the carrying capacity because of the balance between available resources and reproduction rate.
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Math Problem Analysis
Mathematical Concepts
Logistic Growth
Differential Equations
Population Dynamics
Formulas
dP/dt = P(2 - P/5000)
P(t) = K / (1 + Ce^(-rt))
Theorems
Logistic Growth Model
Suitable Grade Level
Grades 11-12
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